Question

我收到了这段代码，该代码链接到索引页面上的搜索字段：

<?php
   ini_set('display_errors', 2);
   $search = $_GET ['q'];
   $conn = mysqli_connect("localhost", "root", "","release");
   $query    = mysqli_query($conn,"SELECT * FROM game WHERE game_name LIKE '%". $search ."%'");
   $foundnum = mysqli_fetch_assoc($query); 
   $count = count($foundnum['game_name']);


   if ($foundnum == 0) {
      echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
      }
         else {
           while($foundnum= mysqli_fetch_assoc($query))
           {
              echo "$count result(s) found!<p>";
              echo"<pre/>";print_r($foundnum['game_name']);
              echo"<pre/>";print_r($foundnum['game_release']);
           }
      }
?>

在没有while循环的情况下，一切正常，但由于某些搜索字词（例如“汽车”）应该同时打印“项目CARS”和“崛起的化身”，我需要一个while - 循环。

我也尝试将while - 循环放在if - 语句之前，但这也不起作用。我做错了什么？

Answer 1

我已在您的代码中进行了一些更正..请使用以下代码重新进行修改

我已经使用我的数据库表尝试了代码，它显示了正确的值......

    <?php
    ini_set('display_errors', 1);
    $search = $_GET['q'];
    $conn = mysqli_connect("localhost", "root", "", "release");
    $query = mysqli_query($conn, "SELECT * FROM game WHERE game_name LIKE '%" . $search . "%'");
    $count = mysqli_num_rows($query); // right way to find row count

    if ($count == 0)
    {
        echo "No results found. Either this game doesn't exist, or we have yet to add it. Please contact us!";
    }
    else
    {
        while ($foundnum = mysqli_fetch_assoc($query))
        {
            echo "$count result(s) found!<p>";
            echo"<pre>";
            print_r($foundnum['game_name']);
            echo"</pre><pre>";
            print_r($foundnum['game_code']);
            echo"</pre>";
        }
    }
    ?>

如果你想搜索insensitively（即忽略大写和小写字母）而不是让我知道..我会更新代码

while循环中的while循环不会打印所有答案

1 个答案: