Question

$input['activities'] = array(3,2,5);

foreach($input['activities'] as $activity_id){

    $user_activities = new User_activities;

    $user_activities->activity_id = $activity_id;

    $user_activities->user_id = Auth::id();

    $user_activities->save();

}

是否可以使用单行脚本为Laravel中的每个语句执行上述操作？而不是在foreach中进行保存，是否可以在一行中进行保存？

Answer 1

只需将数组数组传递给Eloquent::insert()：

$data = [];

foreach($input['activities'] as $activity_id) {
    $data[] = [
        'activity_id' => $activity_id,
        'user_id' => Auth::id()
    ];
}

Coder::insert($data);

Answer 2

我找到了解决方案，

$activities = array(3,2,5);
$user->activities()->sync($activities);

用户模型的活动功能如下，

public function activities()
{
    return $this->belongsToMany('App\Activity', 'user_activities')->select(['activities.id'])->withTimestamps();
}

Laravel，不使用foreach插入多行

2 个答案: