我遇到了JavaScript,webRTC和Kurento的问题。我自己无法解决这个问题。我试图将来自本地变量的远程流放在全局变量中,但是我遇到了一些麻烦。我尝试解释所有解决问题的步骤: 第一步,我有Kurento webRtcEndpoint函数:
webRtcPeer = kurentoUtils.WebRtcPeer.startRecvOnly(videoElement, onPlayOffer, onError);
它调用函数" onPlayOffer"那就是:
function onPlayOffer(sdpOffer) {
co(function * () {
try {
if (!client) client = yield kurentoClient(args.ws_uri);
pipeline = yield client.create('MediaPipeline');
var webRtc = yield pipeline.create('WebRtcEndpoint');
var player = yield pipeline.create('PlayerEndpoint', { uri: args.file_uri });
yield player.connect(webRtc);
var sdpAnswer = yield webRtc.processOffer(sdpOffer);
webRtcPeer.processSdpAnswer(sdpAnswer, recordVideo);
console.log('DEBUG: ok, AGAIN, localStream: ');
console.log(localStream);
yield player.play();
我已经编辑了函数processSdpAnswer以这种方式获取流:
WebRtcPeer.prototype.processSdpAnswer = function(sdpAnswer, callbackEvent, successCallback) {
//WebRtcPeer.prototype.processSdpAnswer = function(sdpAnswer, successCallback) {
var answer = new RTCSessionDescription({
type : 'answer',
sdp : sdpAnswer,
});
console.log('Kurento-Utils: SDP answer received, setting remote description');
var self = this;
self.pc.onaddstream = function(event) {
var objectURL = URL.createObjectURL(event.stream);
//Added the string below to create the callback
callbackEvent(event.stream);
};
self.pc.setRemoteDescription(answer, function() {
if (self.remoteVideo) {
var stream = self.pc.getRemoteStreams()[0];
//console.log('Kurento-Utils: Second self.pc');
//console.log(self.pc)
self.remoteVideo.src = URL.createObjectURL(stream);
}
if (successCallback) {
successCallback();
}
}, this.onerror);
因此,在这种情况下,回调是函数recordVideo,它被传递" event.stream"
function recordVideo(stream) {
console.log("DEBUG: called function recordVideo()");
localStream = stream;
console.log("DEBUG: Copied stream -> localStream:");
console.log(localStream);
console.log("DEBUG: the stream object contains:");
console.log(stream);}
所以我希望在函数" onPlayOffer"我可能将对象localStream(全局声明)作为流的副本(即本地)。变量" stream"是正确的,变量" localStream"相反,它是未定义的。
你可以帮我理解为什么吗? 我已经读过,问题可能是控制台,但是我试图评论所有console.log行没有成功。你能帮助我吗?谢谢大家!(如果有人知道在全球范围内采用event.stream对象的更快方式,我将感谢您的帮助!)
答案 0 :(得分:2)
你是对的,你的问题是异步的,
最简单的纠正方法是,将任何必须遵循异步调用的代码/逻辑作为该异步调用的回调,
可以通过更改
来完成 ...
webRtcPeer.processSdpAnswer(sdpAnswer, recordVideo);
console.log('DEBUG: ok, AGAIN, localStream: ');
console.log(localStream);
yield player.play();
...
进入
...
var callback = function (){
console.log('DEBUG: ok, AGAIN, localStream: ');
console.log(localStream);
yield player.play();
};
webRtcPeer.processSdpAnswer(sdpAnswer, recordVideo.bind({callback: callback})); // through bind, we are setting the `this` value of the recordVideo.
并将recordVideo修改为
function recordVideo(stream) {
...
this.callback(); // extra line added.
}
答案 1 :(得分:1)
你错过了收益率,这就是下面的代码:
webRtcPeer.processSdpAnswer(sdpAnswer, recordVideo);
在recordVideo之前执行
解决它只是改为
yield webRtcPeer.processSdpAnswer(sdpAnswer, recordVideo);