我有缩放地图的问题。实际问题是,当我缩放地图时,使用笑脸在地图上显示的位置也可以缩放,但我不想放大笑脸。它可以保持相同的大小和地点。有时笑脸会重叠,所以为了避免这种情况,我试图解决上述问题,但我不知道如何在d3.js地图上包含转换属性,包括图像和文本等许多内容。请看看jsfiddle链接,你可以看到在日本3笑脸得到重叠并保持重叠,即使在缩放地图后。
我的代码如下:
<!DOCTYPE html>
<meta charset="utf-8">
<style>
path {
stroke: white;
stroke-width: 0.25px;
fill: grey;
}
</style>
<body>
<script src="http://d3js.org/d3.v3.min.js"></script>
<script src="http://d3js.org/topojson.v0.min.js"></script>
<script>
var width = 960,
height = 500;
var data = [
{
"code":"TYO",
"city":"TOKYO",
"country":"JAPAN",
"lat":"35.68",
"lon":"139.76"
},
{
"code":"OSK",
"city":"Osaka",
"country":"JAPAN",
"lat":" 34.40",
"lon":"135.37"
},
{
"code":"HISH",
"city":"Hiroshima",
"country":"JAPAN",
"lat":"34.3853",
"lon":"132.4553"
},
{
"code":"BKK",
"city":"BANGKOK",
"country":"THAILAND",
"lat":"13.75",
"lon":"100.48"
},
{
"code":"DEL",
"city":"DELHI",
"country":"INDIA",
"lat":"29.01",
"lon":"77.38"
},
{
"code":"SEA",
"city":"SEATTLE",
"country":"USA",
"lat":"38.680632",
"lon":"-96.5001"
}
];
var projection = d3.geo.mercator()
.center([0, 5 ])
.scale(200)
.rotate([-180,0]);
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var path = d3.geo.path()
.projection(projection);
var g = svg.append("g");
// load and display the World
d3.json("world-110m2.json", function(error, topology) {
// load and display the cities
function drawMap(data){
var circle = g.selectAll("circle")
.data(data)
.enter()
.append("g")
circle.append("circle")
.attr("cx", function(d) {
return projection([d.lon, d.lat])[0];
})
.attr("cy", function(d) {
return projection([d.lon, d.lat])[1];
})
.attr("r", 5)
.style("fill", "red");
circle.append("image")
.attr("xlink:href", "http://fc08.deviantart.net/fs71/f/2013/354/8/7/blinking_smiley__animated__by_mondspeer-d6ylwn3.gif")//http://t2.gstatic.//com/images?q=tbn:ANd9GcT6fN48PEP2-z-JbutdhqfypsYdciYTAZEziHpBJZLAfM6rxqYX";})
.attr("class", "node")
.attr("x", function(d) {
return (projection([d.lon, d.lat])[0]) - 8;
})
.attr("y", function(d) {
return (projection([d.lon, d.lat])[1])-8;
})
.attr("width",20)
.attr("height",20)
//});
}
g.selectAll("path")
.data(topojson.object(topology, topology.objects.countries)
.geometries)
.enter()
.append("path")
.attr("d", path)
drawMap(data);
});
// zoom and pan
var zoom = d3.behavior.zoom()
.on("zoom",function() {
g.attr("transform","translate("+
d3.event.translate.join(",")+")scale("+d3.event.scale+")");
g.selectAll("circle")
.attr("d", path.projection(projection));
g.selectAll("path")
.attr("d", path.projection(projection));
});
svg.call(zoom)
</script>
</body>
</html>
任何身体帮我缩放地图图片而不是笑脸
答案 0 :(得分:1)
实现语义缩放:)
尝试使用此示例更改代码:):
Semantic zoom on map with circle showing capital
JSFIDDLE:http://jsfiddle.net/xf7222dg/2/
下面的代码缩小了&#39;圈子&#39;取决于规模
var zoom = d3.behavior.zoom()
.on("zoom",function() {
g.attr("transform","translate("+
d3.event.translate.join(",")+")scale("+d3.event.scale+")");
g.selectAll("circle")
.attr("r", function(){
var self = d3.select(this);
var r = 8 / d3.event.scale; // set radius according to scale
self.style("stroke-width", r < 4 ? (r < 2 ? 0.5 : 1) : 2); // scale stroke-width
return r;
});
});
这是与你的笑脸合作:http://jsfiddle.net/dmn0d11f/7/
你必须改变宽度&#39;节点(图像)不是像圆圈一样的半径。因此,选择节点,而不是更改&#39; r&#39;改变宽度&#39; :
g.selectAll(".node")
.attr("width", function(){
var self = d3.select(this);
var r = 28 / d3.event.scale; // set radius according to scale
self.style("stroke-width", r < 4 ? (r < 2 ? 0.5 : 1) : 2); // scale stroke-width
return r;
});