def to_pig_latin(s):
j = 0 # points to first character in word
i = 0
new_sentence_1 = '' # variable to store strings being changed
vowel_position = 0 # show the position of the first vowel
number_of_words = 0
number_of_spaces = s.count(" ")
number_of_words = number_of_spaces + 1
space_position = s.find(" ") # find the position of the first space
sent = s[:space_position] # slice the first word of the sentence
old_sent = s[len(sent)+1:] # stores the old sentence without the first word of s
while number_of_spaces >= 0:
if sent[j] in ["a", "e", "i", "o", "u"]: # checks if first character is a vowel
new_sentence = sent + "way" # adds 'way' to the first word
new_sentence_1 = new_sentence_1 + ' ' + new_sentence # adds the words
else: # if first character is not equal to a vowel
for i in range(len(sent)):
# check to see if first character in s is a vowel
if s[i] == 'a':
break
if s[i] == 'e':
break
if s[i] == 'i':
break
if s[i] == 'o':
break
if s[i] == 'u':
break
vowel_position = i # takes position of first vowel reached in word
consonant_sequence = sent[:vowel_position] # stores all the consonants up to the first vowel, but not the first vowel
sent = sent[vowel_position:] # slices the word from the first vowel to the end
new_sentence = sent + 'a' + consonant_sequence + 'ay' # adds strings
new_sentence_1 = new_sentence_1 + ' ' + new_sentence # adds the words
s = old_sent # takes the value of old_sent
space_position = s.find(" ") # find the position of the first space
即使s中有一个字，我如何更改下面的部分才能检查？或者，如果字符串s中的最后一个单词以一个以一个或多个辅音开头的单词结尾？
if space_position == -1:
space_position = len(s)
sent = s[:space_position]
if sent[j] in ["a", "e", "i", "o", "u"]:
new_sentence = sent + "way"
new_sentence_1 = new_sentence_1 + ' ' + new_sentence
break
else:
for i in range(len(sent)):
if s[i] == 'a':
break
if s[i] == 'e':
break
if s[i] == 'i':
break
if s[i] == 'o':
break
if s[i] == 'u':
break
vowel_position = i
consonant_sequence = sent[:vowel_position]
sent = sent[vowel_position:]
new_sentence = sent + 'a' + consonant_sequence + 'ay'
new_sentence_1 = new_sentence_1 + ' ' + new_sentence
sent = s[:space_position]
old_sent = s[len(sent)+1:]
number_of_spaces = s.count(" ")
number_of_words = number_of_spaces + 1
return new_sentence_1[1:]
英语/ piglatin翻译的测试程序：
import piglatin
choice = input ("(E)nglish or (P)ig Latin?\n")
action = choice[:1]
if action == 'E':
s = input("Enter an English sentence:\n")
new_s = piglatin.to_pig_latin(s)
print("Pig-Latin:")
print(new_s)
elif action =='P':
s = input("Enter a Pig Latin sentence:\n")
new_s = piglatin.to_english(s)
print("English:")
print(new_s)
输出：
(E)nglish or (P)ig Latin? E
Enter an English sentence: My friend next to me is wearing a shoe
Traceback (most recent call last):
File "/Applications/Wing101.app/Contents/Resources/src/debug/tserver/_sandbox.py",
line 9, in <module>
File "/Users/azhar/Desktop/Computer Science/Assignments/Assignment 4 (Functions & Strings)/piglatin.py", line 46, in to_pig_latin
if sent[j] in ["a", "e", "i", "o", "u"]: # checks if first value in j is equal to a vowel
builtins.IndexError: string index out of range
答案 0 :(得分：0)
我认为，不是修复那个特定问题，而是简化代码会更容易。
首先，您可以使用s.split()拆分句子，这将为您提供在空白处拆分的单词列表。其次，您可以使用s.find()来查找给定字符串的索引。第三，您可以使用' '.join(sen)使用空格加入字符串列表。
因此，使用这些，您的代码减少到此（我还添加了大写的处理）：
def to_pig_latin(sen):
senlst = sen.lower().split() # split into list of words
for i, word in enumerate(senlst):
if word[0] in 'aeiou':
senlst[i] += 'way'
else:
for vow in 'aeiou':
ind = word.find(vow)
if ind >= 0:
break
if ind < 0: # no vowel in word
continue
senlst[i] = word[ind:]+'a'+word[:ind]
newsen = ' '.join(senlst) # combine list of words into sentence
if sen[0].isupper(): # make capitalization like original
newsen = newsen.capitalize()
return newsen
但是，如果你真的想检查一下是否有一个词，你可以if s.strip():。这将做的是剥离和前导或尾随空格。如果没有单词，这将为您留下一个空字符串。在python中，空字符串（或空列表或元组）被视为False，因此您可以在if测试中使用它，然后对您想要的那种情况进行任何处理。