我正在尝试用attiny85锻炼蓝牙钥匙扣

Question

我收到一个字符“1”然后蜂鸣器应该连续发声如果字符“2”收到，那么蜂鸣器应该关闭

void loop()
{    
    if (mySerial.available()) // there is some data to read
    {
        receivedChar = mySerial.read();

        if (receivedChar == '1') 
        {
            mySerial.println("Received a 1"); // for debugging
            digitalWrite(LED, HIGH);
            tone(buz, 1000, 500);
        }

        if (receivedChar == '2')
        {
            mySerial.println("Received a 2"); // for debugging
            digitalWrite(LED, LOW);
        }
    }
}

但是这里蜂鸣器没有循环或重复。你能建议其他吗？只需蜂鸣器即可完成，无需任何LED发光。