Question

我想将我想用GUI打开的文件目录存储到记事本中。我能够正确读取文件，但是当我想引用它时，我无法打开文件我的代码：

File desktop = new File(System.getProperty("user.home"), "Desktop");
File sharepoint = new File(System.getProperty("user.home"), "SharePoint");

try {
    File file= new File("C:/Users/user/Desktop/File.txt");
    FileReader fr = new FileReader(file);
    BufferedReader br = new BufferedReader(fr);
    StringBuffer str = new StringBuffer();
    String line;
    while((line=br.readLine())!=null) {
        str.append(line);
        str.append("\n");
    }
    fr.close();
    // Desktop.getDesktop().open(new File(sharepoint + "/Open Project Transition Check - Doc/Project Status Summary/a.xlsb"));
    //Scanner scan = new Scanner(file);
    System.out.println(str.toString());
    Desktop.getDesktop().open(new File(str.toString()));

} catch (Exception ex) {
    JOptionPane.showMessageDialog(null,"Please check that you have SharePoint access, contact your admin for more assistance", "Access error",  JOptionPane.WARNING_MESSAGE);
    // Logger.getLogger(HPform.class.getName()).log(Level.SEVERE, null, ex);
}

Answer 1

这是你的问题

while((line=br.readLine())!=null){
    str.append(line);
    str.append("\n"); <-- what this new line for? if it's not used, delete it
}

即使你的txt文件只有一个文件。问题仍然存在，因为这不是打开文件的有效参数（您的最终结果将是C:\Users\user\SharePoint\Open Project Transition Check - Doc\Project Status Summary\a.xlsb\n）

在记事本中存储了一个文件目录，但在使用Java引用它时无法打开它

1 个答案: