Question

回复是：

<?xml version="1.0" encoding="UTF-8"?><soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">   <soapenv:Header>
    <platformMsgs:documentInfo xmlns:platformMsgs="urn:messages_2014_2.platform.webservices.netsuite.com">
      <platformMsgs:nsId>WEBSERVICES_TSTDRV1371590_041220151334115279325827527_fefe8c</platformMsgs:nsId>
    </platformMsgs:documentInfo>   </soapenv:Header>   <soapenv:Body>
    <addResponse xmlns="">
      <platformMsgs:writeResponse xmlns:platformMsgs="urn:messages_2014_2.platform.webservices.netsuite.com">
        <platformCore:status xmlns:platformCore="urn:core_2014_2.platform.webservices.netsuite.com" isSuccess="true"/>
        <platformMsgs:baseRef xmlns:platformCore="urn:core_2014_2.platform.webservices.netsuite.com" internalId="5450" type="customer" xsi:type="platformCore:RecordRef"/>
      </platformMsgs:writeResponse>
    </addResponse>   
</soapenv:Body> 
</soapenv:Envelope>

如何使用groovy我的代码获取此xml的内部Id：

def slurper = new XmlSlurper（）。parseText（response.text）;

Answer 1

你的意思是：

def slurper = new XmlSlurper().parseText(response.text);
def id = slurper.Body.addResponse.writeResponse.baseRef.@internalId

assert id == '5450'

Answer 2

最简单的答案：

def slurper = new XmlSlurper().parseText(response.text)
def internalId = slurpXml['Body']['addResponse']['writeResponse']['baseRef'].attribute('internalId')

当然，这完全忽略了命名空间。不过，你不必在你的例子中担心它。

如何在Netsuite中解析XML并在groovy中获取特定值

2 个答案: