你好我几天前问了一个类似的问题而没有任何回复。我试图自己解决这个问题而没有成功。 我成功地使用了服务器发送请求,该请求轮询数据库以获取新条目,并成功获取以json格式返回的数据(在webconsole中确认)。我似乎无法做的是在eSource.onmessage函数中的其他函数中使用数据。
这是jquery
<script type="text/javascript">
$(document).ready(function() {//READY FUNC
//check for browser support
if(typeof(EventSource)!=="undefined") {
//create an object, passing it the name and location of the server side script
var eSource = new EventSource("http://newberylodge.co.uk/webapp/includes/messageRetrieve.php");
//detect message receipt
eSource.onmessage = function(event) {
//write the received data to the page
$.each(data, function(key, val) {
//iterate each data
var id = val.id;
var messageId = val.messageId;
var messageSubject = val.messageSubject;
var messageContent = val.messageDetail;
$('#serverData').append('<div id="' + id + '" class="messageAlert">' + messageSubject + '</div>');
$('#serverData').append('<div id="' + messageId + '" class="messageContent">' + messageContent + '</div>');
$('#' +messageId).append('<input id="' + messageId + '" type="button" class="deleteButton" value="Delete Message" />');
});
//EACH DATA
}
$(document).on('click', '#' +messageId, function(){
//on click
$.post("http://newberylodge.co.uk/webapp/includes/deleteMessage.php",{value1 : messageId}, function() {
location.reload(true);
alert('Message Deleted');
});
//POST AJAX
});
//END ON CLICK
};
//TYPE OF EVENT SOURCE
});
//DOCUMENT READY FUNC
</script>
这是PHP处理页面messageReturn.php
<?php
include_once 'db_connect.php';
$return_arr = array();
$result = mysqli_query($mysqli, "SELECT * FROM message");
while($row = mysqli_fetch_array($result)) {
$row_array['id'] = $row['id'];
$row_array['messageId'] = $row['messageId'];
$row_array['messageSubject'] = $row['messageSubject'];
$row_array['messageDetail'] = $row['messageDetail'];
array_push($return_arr,$row_array);
}
header('Content-Type: text/event-stream');
header('Cache-Control: no-cache');
echo json_encode($return_arr);
flush();
?>
我相信我错了,但不知道怎么回事
eSource.onmessage = function(event) {
//write the received data to the page
$.each(data, function(key, val) {
//iterate each data
var id = val.id;
var messageId = val.messageId;
var messageSubject = val.messageSubject;
var messageContent = val.messageDetail;
$('#serverData').append('<div id="' + id + '" class="messageAlert">' + messageSubject + '</div>');
$('#serverData').append('<div id="' + messageId + '" class="messageContent">' + messageContent + '</div>');
$('#' +messageId).append('<input id="' + messageId + '" type="button" class="deleteButton" value="Delete Message" />');
});
//EACH DATA
}
我要做的是从响应中获取json数据,以便我可以在脚本中的其他函数中使用它。 有人可以帮忙吗?
答案 0 :(得分:1)
您收到的消息是一个JSON字符串,在将其解析为Javascript对象之前无法进行迭代。
其次,您似乎没有任何数据,您使用的是data
,但它从未在任何地方定义过,您想要的是event.data
if (typeof (EventSource) !== "undefined") {
var eSource = new EventSource("http://newberylodge.co.uk/webapp/includes/messageRetrieve.php");
eSource.onmessage = function (event) {
var data = JSON.parse(event.data);
$.each(data, function (key, val) {
var id = val.id;
var messageId = val.messageId;
var messageSubject = val.messageSubject;
var messageContent = val.messageDetail;
$('#serverData').append('<div id="' + id + '" class="messageAlert">' + messageSubject + '</div>');
$('#serverData').append('<div id="' + messageId + '" class="messageContent">' + messageContent + '</div>');
$('#' + messageId).append('<input id="' + messageId + '" type="button" class="deleteButton" value="Delete Message" />');
});
}
.... etc