Question

我正在尝试编写一个使用滑动功能的应用。每次用户滑动手机时，都会生成一个随机数，该数字用于获取数组myNames []中的字符串值，并显示在textView上。我想使用行或任何文本消息应用程序共享textView上显示的值。我的最终问题是：为什么shareIntent不识别textView.getText（）。toString（）;并启用该字符串值的共享？我一直试图解决这个问题几天，并且无法弄清楚为什么每次刷卡开始时它都不会更新值。

public class MainActivity extends Activity {
float x1, x2;
float y1, y2;
SharedPreferences preferences;
ShareActionProvider provider;
TextView textView;
String z;
private ShareActionProvider mShareActionProvider;

final String myNames[] = {"1","2","3","4","5","6"};
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    textView = (TextView) findViewById(R.id.textView1);
    Typeface font = Typeface.createFromAsset(getAssets(),
            "fonts/example.ttf");

    textView.setTypeface(font);

}

public boolean onTouchEvent(MotionEvent touchevent) {
    Random randGen = new Random();
    int rando =randGen.nextInt(myNames.length);

    switch (touchevent.getAction()) {

    // when user first touches the screen we get x and y coordinate
    case MotionEvent.ACTION_DOWN: {
        x1 = touchevent.getX();
        y1 = touchevent.getY();
        break;
    }
    case MotionEvent.ACTION_UP: {
        x2 = touchevent.getX();
        y2 = touchevent.getY();

        if (x1 < x2) {

            textView.setText(myNames[rando]);

        }

        // if right to left sweep event on screen
        if (x1 > x2) {
            textView.setText(myNames[rando]);
        }
    }
    }z=myNames[rando];

    return false;
}

public boolean onCreateOptionsMenu(Menu menu) {
    String y="yolo";

    getMenuInflater().inflate(R.menu.main, menu);
    MenuItem shareItem = (MenuItem) menu.findItem(R.id.action_share);

    ShareActionProvider mShare = (ShareActionProvider) shareItem
            .getActionProvider();
    Intent shareIntent = new Intent(Intent.ACTION_SEND);

    shareIntent.setAction(Intent.ACTION_SEND);
    shareIntent.setType("text/plain");

    shareIntent.putExtra(Intent.EXTRA_TEXT, "text to sahre test: " + textView.getText().toString()
            );

    mShare.setShareIntent(shareIntent);

    return true;
}

}

Answer 1

onCreateOptionsMenu()只运行一次 - 最初创建菜单时。

您应该保存对ShareActionProvider的引用，并在每次setShareIntent()的文字更改时（例如，作为TextView的一部分）致电ACTION_UP。< / p>

ShareIntent不会从textView更新值

1 个答案: