Question

我正在编写一个加载到状态栏的简单应用程序，单击它时会在状态栏图标下打开一个弹出窗口。我正在使用故事板来定义我想在我的popover中显示的UI。事情就是我在实例化故事板时打开一个窗口。我怎么能防止这种情况？这是我的应用程序委托中的代码：

func applicationDidFinishLaunching(aNotification: NSNotification) {
    let mainBoard = NSStoryboard(name: "MainBoard", bundle: nil)
}

Answer 1

import Cocoa

@NSApplicationMain
class AppDelegate: NSObject, NSApplicationDelegate {
    var defaultWindow:NSWindow!
    func applicationDidFinishLaunching(aNotification: NSNotification) {
        defaultWindow = NSApplication.sharedApplication().windows.first as? NSWindow
        defaultWindow.close()

    }
    func applicationWillTerminate(aNotification: NSNotification) {
        // Insert code here to tear down your application
    }
    @IBAction func menuClick(sender: AnyObject) {
        defaultWindow.makeKeyAndOrderFront(nil)
    }
}

更新： Xcode 7.1.1•Swift 2.1

NSApplication.sharedApplication().windows.first?.close()

如何防止故事板打开一个窗口

1 个答案: