Question

我必须在我的django网址中用模拟在url中写一个正则表达式，文件的路径是什么？哪里有“目录”，“子目录”和“文件”，每个对象的模型都有“slug”。

我已经这样做了：

model.py

class Directory(models.Model):
    name = models.CharField(max_length=100)
    slug = models.SlugField(max_length=100, unique=True,)
    subdirectory = models.ForeignKey('self', null=True, blank=True)

class File(models.Model):
    name = models.CharField(max_length=100)
    slug = models.SlugField(max_length=100, unique=True,)
    directory = models.ForeignKey(Directory)

views.py

class DirectoryView(generic.DetailView):
    model = Directory
    template_name = 'appname/directory.html'


class FileView(generic.DetailView):
    model = File
    template_name = 'appname/file.html'

应用程序名称/ urls.py

urlpatterns = [
    url(r'^(?P<slug>[-\w]+)/$',
        views.DirectoryView.as_view(), name='directory'),
    url(r'^(?P<slug1>[-\w]+)/(?P<slug>[-\w]+)/$',
        views.FileView.as_view(), name='file'),
]

“file1.txt”的结果网址是：

folder1中
文件夹2
- subfolder1
  - FILE1.TXT

的http：/mydomain.com/appname/subfolder1/file1txt

但我需要它：

的http：/mydomain.com/appname/的文件夹2 / subfolder1 / file1txt

谢谢，

伊万

Answer 1

所以我终于在这个django片段中找到了答案：

https://djangosnippets.org/snippets/362/

这就是我最后得到的结果：

<强> models.py

class Directory(models.Model):
    name = models.CharField(max_length=100)
    slug = models.SlugField(max_length=100, unique=True,)
    parent = models.ForeignKey('self', null=True, blank=True)

    def get_absolute_url(self):
        url = "/%s/" % self.slug
        cwd = self
        while cwd.parent:
            url = "/%s%s" % (cwd.parent.slug, url)
            cwd = cwd.parent
        return url

class File(models.Model):
    name = models.CharField(max_length=100)
    slug = models.SlugField(max_length=100, unique=True,)
    directory = models.ForeignKey(Directory)

<强> views.py

from django.http import Http404
from django.shortcuts import render, get_object_or_404
from .models import Archive, Directory, File

def directories(request, full_slug):
    slugs = full_slug.split('/')
    cwd_slug = slugs[-1]
    directory = get_object_or_404(Directory, slug=cwd_slug)
    if not directory.get_absolute_url().strip('/') == full_slug:
        raise Http404
    # if you reach this line, you've found the directory

    context = {'directory': directory}
    template = 'appname/directory.html'
    return render(request, template, context)


def files(request, full_slug, file_slug):
    slugs = full_slug.split('/')
    cwd_slug = slugs[-1]
    directory = get_object_or_404(Directory, slug=cwd_slug)
    if not directory.get_absolute_url().strip('/') == full_slug:
        raise Http404
    files = get_object_or_404(File, name=file_slug)
    # if you reach this line, you've found the file

    context = {'archive': archive_slug, 'directory': full_slug, 'file': files}
    template = 'getdocs/file.html'
    return render(request, template, context)

<强>应用程序名称/ urls.py

from django.conf.urls import url, include
from . import views

file_patterns = [
    url(r'^$', views.directories, name='directory'),
    url(r'^(?P<file_slug>(.*)[.]{1}[-\w]{3})$', views.files, name='file'),
]

urlpatterns = [
    url(r'^(?P<full_slug>(.*))/', include(file_patterns)),
]

我希望这有助于其他人。

django urls中的正则表达式用于自引用模块

1 个答案: