解析不起作用json Android

Question

解析不适用于json Android 解析不起作用json Android

{
"group_name":"МБА-14",
 "days":[
{
 "weekday":1,
"lessons":[
 {
 "subject":"Научно-исследовательский семинар",
 "type":0,
"time_start":"17:10",
 "time_end":"18:30",
"time_number":6,
"parity":1
}
]
}
]
}

我需要在工作日获得价值。这是我的代码：

JSONObject jsonObject=new JSONObject(str);
            JSONObject jsonObject1=jsonObject.getJSONObject("weekday");
            Log.e("aaaa", jsonObject1.toString() );

Answer 1

JSONArray days = jsonObject.getJSONArray("days");
JSONObject oneDay = days.getJSONObject(0);
int weekday = oneDay.getInt("weekday");

Answer 2

如果你的“str”变量包含这个， 然后解析像

JSONObject jsonObject=new JSONObject(str);
JSONArray jArray = jsonObject.getJSONArray("days");
String weekday = (jArray .getJSONObject(0)).getString("weekday");