我有这样的数组结构:
阵列(
[1.1] => INTEGER: 1
[1.2] => INTEGER: 2
[1.3] => INTEGER: 3
[1.4] => INTEGER: 4
[1.5] => INTEGER: 5
[1.6] => INTEGER: 6
[2.1] => STRING: lo
[2.2] => STRING: eth0
[2.3] => STRING: eth1
[2.4] => STRING: wifi0
[2.5] => STRING: ath0
[2.6] => STRING: br0
[3.1] => INTEGER: softwareLoopback(24)
[3.2] => INTEGER: ethernetCsmacd(6)
[3.3] => INTEGER: ethernetCsmacd(6)
[3.4] => INTEGER: ethernetCsmacd(6)
[3.5] => INTEGER: ethernetCsmacd(6)
[3.6] => INTEGER: ethernetCsmacd(6)
)
我需要将单独的数组放入像这样的新组多维数组
阵
(
[0] =>数组(
[0] =>整数:1
[1] => STRING:lo
[2] => INTEGER:softwareLoopback(24)
)
.....
)
答案 0 :(得分:2)
如果它总是6的组,那么chunk和transpose:
$myArray = [
'1.1' => 'INTEGER: 1',
'1.2' => 'INTEGER: 2',
'1.3' => 'INTEGER: 3',
'1.4' => 'INTEGER: 4',
'1.5' => 'INTEGER: 5',
'1.6' => 'INTEGER: 6',
'2.1' => 'STRING: lo',
'2.2' => 'STRING: eth0',
'2.3' => 'STRING: eth1',
'2.4' => 'STRING: wifi0',
'2.5' => 'STRING: ath0',
'2.6' => 'STRING: br0',
'3.1' => 'INTEGER: softwareLoopback(24)',
'3.2' => 'INTEGER: ethernetCsmacd(6)',
'3.3' => 'INTEGER: ethernetCsmacd(6)',
'3.4' => 'INTEGER: ethernetCsmacd(6)',
'3.5' => 'INTEGER: ethernetCsmacd(6)',
'3.6' => 'INTEGER: ethernetCsmacd(6)',
];
$newArray = call_user_func_array(
'array_map',
array_merge(
array(NULL),
array_chunk($myArray, 6)
)
);
var_dump($newArray);
答案 1 :(得分:0)
以“标准方式”重新索引输入数组(我的意思是索引0,1,2 ......)然后你可以编写以下函数
$a = array(1,2,3,21,22,23,31,32,33); // input array - example
function rearrange($a) {
$r = array();
$count = count($a) / 3;
for ($i = 0; $i<$count; $i++) {
$r[$i] = array(
0 => $a[$i],
1 => $a[$i+$count],
2 => $a[$i+2*$count]
);
}
return ($r);
}
var_dump($a);
$a = rearrange($a);
var_dump($a);