Question

我已经通过bootstrap表单构建器构建了一个表单，该表单构建器有两个复选框组，其中第一组有6个复选框＆amp;第二个是有5个复选框。当我填写表格时，以下列方式发布值。

{
  "Hobbies#14287284244583705#reading": "Reading"
},
{
  "Hobbies#14287284244603527#sports": "Sports"
},
{
  "Hobbies#14287284244603819#dancing": "Dancing"
},
{
  "Hobbies#142872842446043#watching_tv": "Watching TV"
},
{
  "Hobbies#14287284244614612#swimming": "Swimming"
},
{
  "Hobbies#14287284244611702#meeting_new_people": "Meeting new people"
},
{
  "Education#14287284244615059#bachelors": "BAchelors"
},
{
  "Education#14287284244629279#masters": "MAsters"
},
{
  "Education#1428728424462974#ms": "MS"
},
{
  "Education#14287284244629849#surgeon": "Surgeon"
},
{
  "Education#14287284244622498#matric": "Matric"
}

现在我将它存储在我的mongodb数据库中，因为$ key = $ value。但是我在网格视图中显示它时遇到了问题。

我尝试用所有可能的方法对其进行分组，但如果复选框组增加，代码变得过于复杂，则无法轻松实现。如果键是相同的，PHP中是否有任何合并值的函数？

最终输出应该是：

{ "Hobbies":"Reading, Sports, Dancing.....(so on)},
{ "Education":"Masters, .... "}

以上关键方面。目前所有键都不同但我可以通过爆炸功能进行比较可能会爆炸[0]

Answer 1

您应该在HTML代码中为所有爱好复选框使用数组命名，如下所示：

<input type="checkbox" name="Hobbies[] value="Reading"/><label>Reading</label>" <input type="checkbox" name="Hobbies[] value="Sports"/><label>Sports</label>"... 与教育复选框相同。

现在你想print_r($_POST['Hobbies'])。这将为您提供所需的输出。

Answer 2

我认为Ashwani是对的，但是如果仍然希望将对象分组在第一个关键元素上，你可以这样做：

$a = json_decode('[{
  "Hobbies#14287284244583705#reading": "Reading"
},
{
  "Hobbies#14287284244603527#sports": "Sports"
},
{
  "Hobbies#14287284244603819#dancing": "Dancing"
},
{
  "Hobbies#142872842446043#watching_tv": "Watching TV"
},
{
  "Hobbies#14287284244614612#swimming": "Swimming"
},
{
  "Hobbies#14287284244611702#meeting_new_people": "Meeting new people"
},
{
  "Education#14287284244615059#bachelors": "BAchelors"
},
{
  "Education#14287284244629279#masters": "MAsters"
},
{
  "Education#1428728424462974#ms": "MS"
},
{
  "Education#14287284244629849#surgeon": "Surgeon"
},
{
  "Education#14287284244622498#matric": "Matric"
}]', true);

$hash = array();
$out = array();
foreach($a as $n => $nod) $hash[explode('#',key($nod), 2)[0]][] = $nod[key($nod)];
foreach($hash as $k => $v) $out[$k] = implode(',', $v);
var_dump($out);

PHP：如何合并键相同的关联数组的值？

2 个答案: