Question

我有一些PHP提交表单，如果字段没有正确填写或者转到带有“谢谢”消息的其他页面，则应该抛出错误。

这是HTML：

<form id="contact-form" method="post" action="sendformemail.php">
    <fieldset>
      <legend>Contact Me</legend>
      <label for="name">Name:</label>
      <input type="text" id="name" name="user_name" placeholder="Enter your name here" class="clear-right">

      <label for="email">Email:</label>
      <input type="email" id="email" name="user_email" placeholder="Enter your email address here!" class="clear-right">

      <label for="job">Reason for contact:</label>
      <select id="job" name="user_job" class="clear-right">
        <optgroup label="Work">
        <option value="Application Development">Application Development/Design</option>
        <option value="Website Design">Website Development/Design</option>
        <option value="Computer Diagnostics">Computer Diagnostics</option>
        </optgroup>

        <optgroup label="Business">
        <option value="looking for a job">Looking for a Job</option>
        </optgroup>

        <optgroup label="Alternative">
        <option value="Other Reason">Other Reason</option>
        <option value="Ask a question" selected>Ask a Question</option>
        </optgroup>

      </select>

      <label for="textarea">Message:</label>
      <textarea id="textarea" name="user_text" rows="10" cols= "50" placeholder="Write your message here..."></textarea>

      <label style="display:none;" for="address">address</label>
      <input style="display:none;" type="text" id="address" name="address" placeholder="Humans do not enter anything in here." class="clear-right">

    </fieldset>
    <button type="submit" class="secondary">Send Message</button>
   </form>

这是PHP：

        <?php
    if ($_SERVER["REQUEST_METHOD"] == "POST") { 
      $name = trim($_POST["user_name"]);
      $email = trim($_POST["user_email"]);
      $jobtype = trim($_POST["user_job"]);
      $message = trim($_POST["user_text"]);
    }
      else {
        echo "this does not work very well";
      }

      if ($name =="" OR $email == "" OR $jobtype == "" OR $message == "") {
        echo "you must specify a value for name, email address and message";
        exit;
      }
        else {
          echo "this doesnt work";
        }

      foreach ($_POST as $value) {
        if (stripos($value, 'Content-Type:')!== FALSE) {

          echo "There was a problem submitting your form";
          exit;
        }
        else {
          echo "this doesnt work 2";
        }
      }

      if ($_POST["address"] != "") {
        echo "Your form submission has an error.";
        exit;
      }
        else {
          echo "this doesnt work 3";
        }


      require_once('inc/class.phpmailer.php');
      $mail = new PHPMailer();

      if (!$mail->ValidateAddress($email)) {
        echo "You must specify a valid email address";
        exit;
      }
        else {
          echo "this doesnt work 4";
        }

      $email_body = "";
      $email_body = $email_body . "Name: " . $name . "<br>";
      $email_body = $email_body . "Email Address:  " . $email . "<br>";
      $email_body = $email_body . "Reason for comntact:  " . $jobtype . "<br>";
      $email_body = $email_body . "Message:  " . $message;

对于任何观看此内容并想知道问题是什么的人来说，这四行代码就是问题所在。

      Server: smtp.postmarkapp.com
      Ports: 25, 2525, or 587
      Username/Password: ********************
      Authentication: Plain text, CRAM-MD5, or TLS

其他一切都没问题

      $mail->SetFrom($email,$name);

      $address = "me@nickdavies.info";
      $mail->AddAddress($address, "Nick Davies");

      $mail->Subject = $jobtype;

      $mail->MsgHTML($email_body);

      if(!$mail->Send()) { 
        echo "The was a problem sending your message: " . $mail->ErrorInfo;
        exit;
      }
        else {
          echo "this doesnt work 4";
        }

      header("location: contact-thanks.php");
      exit;
?>

我把echo放在条件中以查看错误的位置，但是没有显示错误，只是一个没有任何内容的普通页面。

Answer 1

你的if / else标识不正确，else匹配之前的if子句，所以：

if{

    else {
        echo "this does not work very well";
      }
}

不正确，请再次检查您想要做什么。

正确的是：

if(some_condition){
do some;
}
else{
//code here
}

要检查字段，使用Javascript会更容易，请尝试执行以下操作：

<form name ="form" action="script.php" onsubmit="myFunction()">
Enter name: <input type="text" name="name_field">
<input type="submit" value="Submit">
</form>

 <script>
function myFunction() {
if(document.form.name_field.value== ""){
    alert("empty field");
    //...do something
    return false;
    }
}
</script>

提交包含PHP错误的表单

1 个答案: