Question

我有这些代码和下面的输出。我需要在下面的最终输出中看起来像这样。

<?php

    $path = realpath('/cert/cert/cert/p12');

    $objects = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($path), RecursiveIteratorIterator::SELF_FIRST);
    foreach($objects as $name => $object){
        echo $name ."\n<br>";
    }

    ?>

输出

C:\Cert\Cert\cert\p12\.
C:\Cert\Cert\cert\p12\..
C:\Cert\Cert\cert\p12\24by7
C:\Cert\Cert\cert\p12\24by7\.
C:\Cert\Cert\cert\p12\24by7\..
C:\Cert\Cert\cert\p12\24by7\12312@dsadf.com.p12
C:\Cert\Cert\cert\p12\24by7\asdasda@dasda.com.p12
C:\Cert\Cert\cert\p12\24by7\dfgdf@fsdfs.com.p12
C:\Cert\Cert\cert\p12\24by7\534534@24423423.com.p12
C:\Cert\Cert\cert\p12\24by7\rewry.rewrwe.com.p12

我想删除前五个输出行

C:\Cert\Cert\cert\p12\.
C:\Cert\Cert\cert\p12\..
C:\Cert\Cert\cert\p12\24by7
C:\Cert\Cert\cert\p12\24by7\.
C:\Cert\Cert\cert\p12\24by7\..

使输出像这样的最终输出

 C:\Cert\Cert\cert\p12\24by7\12312@dsadf.com.p12
 C:\Cert\Cert\cert\p12\24by7\asdasda@dasda.com.p12
 C:\Cert\Cert\cert\p12\24by7\dfgdf@fsdfs.com.p12
 C:\Cert\Cert\cert\p12\24by7\534534@24423423.com.p12
 C:\Cert\Cert\cert\p12\24by7\rewry.rewrwe.com.p12

递归迭代器PHP删除前5行输出

0 个答案: