我正在使用python 2.7.9而我当前的问题是由于某种原因,我的OptionMenu
命令无效。以下是我的意思的示例代码。
from Tkinter import *
root = Tk()
var = StringVar()
var.set("Choose a name...")
names = []
# Appends names to names list and updates OptionMenu
def createName(n):
names.append(n)
personName.delete(0, "end")
menu = nameMenu['menu']
menu.delete(0, "end")
for name in names:
menu.add_command(label=name, command=lambda name=name: var.set(name))
# what to run when a name is selected
def selection():
print "Running" # For testing purposes to see when/if selection runs
print var.get()
# Option Menu for names
nameMenu = OptionMenu(root, var, (), command=lambda: selection())
nameMenu.grid(row=0, column=0, columnspan=2)
nameMenu.config(width=20)
# Entry for user to submit name
Label(root, text="Name").grid(row=1, column=0)
personName = Entry(root, width=17)
personName.grid(row=1, column=1)
# Add person Button
Button(root, text="Add Person", width=20, command=
lambda: createName(personName.get())).grid(row=5, column=0, columnspan=2)
mainloop()
此理论程序的目的只是为OptionMenu
添加名称,然后当您选择名称时,它将打印它。我可以为OptionMenu
添加名称,但是当OptionMenu
运行selection()
函数时,它就不会。
现在我最好的猜测是什么错误只是按钮调用的createName()
函数也使用了OptionMenu
的命令,因为行
menu.add_command(label=name, command=lambda name=name: var.set(name))
这周围有吗? OptionMenu
可能有多个命令吗?
答案 0 :(得分:2)
您正走在正确的轨道上......但是您可以将名称传递给selection()
函数,而不是更改StringVar:
from Tkinter import *
root = Tk()
var = StringVar()
var.set("Choose a name...")
names = []
# Appends names to names list and updates OptionMenu
def createName(n):
names.append(n)
personName.delete(0, "end")
menu = nameMenu['menu']
menu.delete(0, "end")
for name in names:
menu.add_command(label=name, command=lambda name=name: selection(name))
# what to run when a name is selected
def selection(name):
var.set(name)
print "Running" # For testing purposes to see when/if selection runs
print name
# Option Menu for names
nameMenu = OptionMenu(root, var, ())
nameMenu.grid(row=0, column=0, columnspan=2)
nameMenu.config(width=20)
# Entry for user to submit name
Label(root, text="Name").grid(row=1, column=0)
personName = Entry(root, width=17)
personName.grid(row=1, column=1)
# Add person Button
Button(root, text="Add Person", width= 20, command=lambda: createName(personName.get())).grid(row=5, column=0, columnspan=2)
mainloop()