我想检查SQLite数据库中是否存在记录,这是我到目前为止所做的。当我搜索已经存在的记录时,我从列表中的EditText获取值。
//code from activity class
public View.OnClickListener searchStation = new View.OnClickListener() {
@Override
public void onClick(View v) {
arrayAdapterList=new ArrayAdapter<String>(SearchAndReview.this,
android.R.layout.simple_list_item_1,
list);
String searchTextFinal=searchText.getText().toString();
dbms.searchStation(searchTextFinal);
Cursor cursor= dbms.searchStation(searchTextFinal);
list.add(searchTextFinal);
arrayAdapterList= new ArrayAdapter<String>(SearchAndReview.this,
android.R.layout.simple_list_item_1, list);
listView.setAdapter(arrayAdapterList);
}
};
//来自databasehelper类的代码
public Cursor searchStation(String name){
SQLiteDatabase database = this.getWritableDatabase();
String searchStationQuery = "SELECT stationName FROM review WHERE stationId='"+ name+"'";
Cursor c =database.rawQuery(searchStationQuery,null);
if (c != null && c.moveToFirst()) {
}
return c;
}
答案 0 :(得分:8)
我在我的应用程序中使用此代码并且它可以实现...
LoginActivity.java
DatabaseHelper dbHelper = new DatabaseHelper(getApplicationContext());
String email_id = email.getText().toString();
boolean dbHelper.isExist(email_id);
// if record is exist then it will return true otherwise this method returns false
使用rawQuery
public boolean isExist(String strEmailAdd) {
db = this.getReadableDatabase();
cur = db.rawQuery("SELECT * FROM " + USER_TABLE + " WHERE email_id = '" + strEmailAdd + "'", null);
boolean exist = (cur.getCount() > 0);
cur.close();
db.close();
return exist;
}
使用db.query
public boolean isExist(String strEmailAdd){
String whereClause = "email_id = ?";
String[] whereArgs = new String[]{strEmailAdd};
db = database.getWritableDatabase();
cur = db.query(USER_TABLE, null, whereClause, whereArgs, null, null, null);
boolean exist = (cur.getCount() > 0);
cur.close();
db.close();
return exist;
}
答案 1 :(得分:2)
从表格中选择一行,你得到的结果是否存在,否则就没有。
public boolean doesStationExist(String name){
final String query = "SELECT stationName FROM review WHERE stationId='"+name+"' LIMIT 1";
try (SQLiteDatabase database = getReadableDatabase();
Cursor c = database.rawQuery(query, null)) {
return c.moveToFirst();
}
}
顺便说一句,从rawQuery
返回的光标永远不会是null
。
修改强>
更新的代码将在try
块完成后关闭数据库和光标。这称为try-with-resources。
答案 2 :(得分:0)
<强> DatabaseManager.java 强>
CGPoint
<强> MainActivity.java 强>
UIAlertAction