Question

我的表格如下

客户

客户表格中包含以下列

sales_ID varchar(50)

product_ID int

ProcessNumber int

CreateDate datetime

客户表的数据如下

1。行

sales_Id "00000020041"

product_ID 1733

ProcessNumber 15

2。行

  sales_Id "00000020041"

  product_ID 1733

  ProcessNumber 15

第3。行

  sales_Id "00000020041"

  product_ID 1733

  ProcessNumber 15

问题：

我想删除除了查询的一行以外的所有行。

我在下面试过

    ;with cte as
    (
    select *,row_number() over(order by sales_ID) RN 
    FROM Customer
    where sales_Id = sales_Id 
    and product_ID  = product_ID 
    and ProcessNumber  = ProcessNumber)

    delete  from cte where RN>1

然而，我所尝试的并不适合我。

如果sales_ID和product_Id以及ProcessNumber等于sales_ID和product_Id以及ProcessNumber ，我如何删除除一行之外的所有行？

Answer 1

您需要在PARTITION BY中使用ROW_NUMBER()

;with cte as
(
select *,row_number() over(PARTITION BY sales_Id,product_ID,ProcessNumber order by (SELECT 1)) RN 
FROM Customer
where sales_Id = sales_Id 
and product_ID  = product_ID 
and ProcessNumber  = ProcessNumber)

delete  from cte where RN>1

Answer 2

您不需要CTE和WHERE子句。以下就足够了。

DELETE FROM (
select *,
row_number() over(
                PARTITION BY sales_Id,product_ID,ProcessNumber 
                ORDER BY Sales_ID
                 ) rown
FROM Customer
            )tbl where rown > 1

Answer 3

在这种情况下，您需要使用DELETE tbl FROM（...）tbl而不是DELETE FROM（...）tbl。

    DELETE tbl
    FROM 
    (
        SELECT *,
        row_number() over(
                        PARTITION BY sales_Id,product_ID,ProcessNumber 
                        ORDER BY Sales_ID
                            ) RowNumber
        FROM Customer
    )tbl 
    WHERE RowNumber > 1

T sql删除相同的行，除了一行查询

3 个答案: