我正在尝试使用android studio连接到xampp localhost通过android模拟器。但我总是得到连接拒绝错误。
我已经阅读并尝试了大多数解决方案，例如将localhost更改为10.0.2.2或127.0.0.1或192.168.0.1，甚至尝试删除http：//或添加端口：8080。但仍然没有运气。
我可以在浏览器中运行localhost / test.php没有问题。但10.0.2.2/test.php不起作用。
和当然我也加入了对manifest.xml的互联网权限。
我甚至尝试了2个版本的代码，但它仍然让我失望。有人可以帮我理解这个吗？
这是显示的错误。
04-10 02:55:15.933 2162-2178/com.example.kitd16.myapplication W/System.err﹕ java.net.ConnectException: failed to connect to /10.0.0.2 (port 80) after 60000ms: isConnected failed: ECONNREFUSED (Connection refused)
这是我尝试过的代码。
URL url = new URL("http://127.0.0.1/cloudtest/test.php");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(30000 /* milliseconds */);
conn.setConnectTimeout(60000 /* milliseconds */);
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
conn.setRequestProperty("charset", "utf-8");
conn.setRequestProperty("Content-Length", "" + et.getText().toString());
conn.setUseCaches(false);
conn.setInstanceFollowRedirects(false);
conn.setDoInput(true);
//Send request
DataOutputStream wr = new DataOutputStream(conn.getOutputStream());
wr.writeBytes(et.getText().toString());
wr.flush();
wr.close();
// Starts the query
conn.connect();
is = (BufferedInputStream) conn.getInputStream();
} catch (Exception ex) {
System.out.println("first error");
ex.printStackTrace();
System.exit(0);
} finally {
if (is != null) {
try {
is.close();
} catch (Exception ex) {
}
}
}
第二版
b.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
final ProgressDialog p = new ProgressDialog(v.getContext()).show(v.getContext(),"Waiting for Server", "Accessing Server");
Thread thread = new Thread()
{
@Override
public void run() {
try{
httpclient=new DefaultHttpClient();
httppost= new HttpPost("http://10.0.0.2/my_folder_inside_htdocs/connection.php"); // make sure the url is correct.
//add your data
nameValuePairs = new ArrayList<NameValuePair>(1);
// Always use the same variable name for posting i.e the android side variable name and php side variable name should be similar,
nameValuePairs.add(new BasicNameValuePair("Edittext_value",et.getText().toString().trim())); // $Edittext_value = $_POST['Edittext_value'];
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
//Execute HTTP Post Request
response=httpclient.execute(httppost);
ResponseHandler<String> responseHandler = new BasicResponseHandler();
final String response = httpclient.execute(httppost, responseHandler);
System.out.println("Response : " + response);
runOnUiThread(new Runnable() {
public void run() {
p.dismiss();
tv.setText("Response from PHP : " + response);
}
});
}catch(Exception e){
runOnUiThread(new Runnable() {
public void run() {
p.dismiss();
}
});
System.out.println("Exception : " + e.getMessage());
}
}
};
thread.start();
答案 0 :(得分：0)
对我来说，使用自己的PC IP地址可以使用Android Studio模拟器。点击按钮后 -
HttpPost httpPost=new HttpPost("http://192.168.104.222/index.php");
我在onCreate方法
protected void onCreate(Bundle savedInstanceState) {
//Strict Mode Policy
StrictMode.ThreadPolicy policy =new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main_activity_login);
eName=(EditText)findViewById(R.id.etName);
}
public void Login(View v){
InputStream is=null;
String name=eName.getText().toString();
List<NameValuePair> nameValuePairs=new ArrayList<NameValuePair>(1);
nameValuePairs.add(new BasicNameValuePair("name",name));
try{
//Setting up the default http client
HttpClient httpClient =new DefaultHttpClient();
//Setting up the http post method & passing the url in case
//of online database and the IP address in case of localhost database
//And the php file which serves as the link between the android app
//and the database.
//Second parameter is the php file to link with database
HttpPost httpPost=new HttpPost("http://192.168.104.222/tutorial.php");
//Passing the nameValue pairs inside the httpPOST
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
//Getting the response
HttpResponse response =httpClient.execute(httpPost);
HttpEntity entity =response.getEntity();
is=entity.getContent();
//confirmation
String msg ="Data Entered Successfully";
}catch(ClientProtocolException e){
Log.e("ClientProtocol","Log_TAG");
e.printStackTrace();
}catch(IOException e){
// Log.e("IO Error","Log_TAG");
e.printStackTrace();
}
}