Question

我有一个json文件，我想在PHP文件中显示它的数据。我尝试使用下面的代码，但它不起作用。

$json_output = file_get_contents("https://gdata.youtube.com/feeds/api/playlists/PL3n6kxxrIGdat31ZIf_7wlqtT3I20OqLL?v=2&alt=jsonc");
$json = json_decode($json_output, true);


foreach($json->data->items->thumbnail as $day) {

   echo $day->sqDefault;
   echo $day->hqDefault;
}

我的json文件是

{"apiVersion":"2.1","data":{"id":"PL3n6kxxrIGdat31ZIf_7wlqtT3I20OqLL","author":"Tutorial top","title":"دورة سيو للمبتدئين [ali baba]","description":"","thumbnail":{"sqDefault":"https://i.ytimg.com/vi/XIhVZqCVqhs/default.jpg","hqDefault":"https://i.ytimg.com/vi/XIhVZqCVqhs/hqdefault.jpg"},"content":{"5":"http://www.youtube.com/p/PL3n6kxxrIGdat31ZIf_7wlqtT3I20OqLL"},"totalItems":31,"startIndex":1,"itemsPerPage":1,"items":[{"id":"PLH_kL5FgJPmdcYTGqaMXFsVJJ-pbR_YyiC1Y73R1tfYY","position":1,"author":"Tutorial top","video":{"id":"Kw8m5S2OhPs","uploaded":"2013-11-10T16:04:28.000Z","updated":"2014-02-18T17:59:36.000Z","uploader":"vkd-nAV91SLMCYNBKGJmsA","category":"People","title":"Beginners SEO Tutorial Course   Intro","description":"","thumbnail":
{"sqDefault":"https://i.ytimg.com/vi/Kw8m5S2OhPs/default.jpg","hqDefault":"https://i.ytimg.com/vi/Kw8m5S2OhPs/hqdefault.jpg"},"player":{"default":"https://www.youtube.com/watch?
v=Kw8m5S2OhPs&feature=youtube_gdata_player","mobile":"https://m.youtube.com/details?v=Kw8m5S2OhPs"},"content":{"5":"https://www.youtube.com/v/Kw8m5S2OhPs?version=3&f=playlists&app=youtube_gdata","1":"rtsp://r8---sn-4g57kues.c.youtube.com/CiULENy73wIaHAn7hI4t5SYPKxMYDSANFEgGUglwbGF5bGlzdHMM/0/0/0/video.3gp","6":"rtsp://r8---sn-
4g57kues.c.youtube.com/CiULENy73wIaHAn7hI4t5SYPKxMYESARFEgGUglwbGF5bGlzdHMM/0/0/0/video.3gp"},"duration":413,"aspectRatio":"widescreen","rating":5.0,"likeCount":"1","ratingCount":1,"viewCount":283,"favoriteCount":0,"commentCount":0,"accessControl":
{"comment":"allowed","commentVote":"allowed","videoRespond":"moderated","rate":"allowed","embed":"allowed","list":"allowed",
"autoPlay":"allowed","syndicate":"allowed"}}}]}}

我想要像这样的输出

sqDefault  |   hqDefault

https://i.ytimg.com/vi/Kw8m5S2OhPs/default.jpg,|https://i.ytimg.com/vi/Kw8m5S2OhPs/hqdefault.jpg

Answer 1

经过多次试验，这种方法运行良好。

我已在我的本地系统中测试过。

这是代码： -

<?php
$json_output = file_get_contents("https://gdata.youtube.com/feeds/api/playlists/PL3n6kxxrIGdat31ZIf_7wlqtT3I20OqLL?v=2&alt=jsonc");
$json = json_decode($json_output);
error_reporting(0);
foreach($json->data->thumbnail as $image) {
   echo $image.",|";
}

?>

<强>输出： -

https://i.ytimg.com/vi/XIhVZqCVqhs/default.jpg,|https://i.ytimg.com/vi/XIhVZqCVqhs/hqdefault.jpg

希望这有帮助

Answer 2

首先，如果您想要将JSON结构作为对象（而不是数组）进行访问，请删除json_decode()的第二个参数，否则最终将数组作为$json。请查看first example以了解其中的差异然后你应该遍历items数组。它的每个元素都有一个video属性，它具有你想要的thumbnail属性

$json_output = file_get_contents("https://gdata.youtube.com/feeds/api/playlists/PL3n6kxxrIGdat31ZIf_7wlqtT3I20OqLL?v=2&alt=jsonc");
$json = json_decode($json_output);
foreach ($json->data->items as $item) {
    echo $item->video->thumbnail->sqDefault;
    echo $item->video->thumbnail->hqDefault;
}

应该做的工作。你可以see it in action。

为了清楚了解结构，许多在线可用的JSON观众可以为您提供帮助;-)

Answer 3

看到我删除了json_decode()中的第二个参数，并且我使用$json->data->items[0]->video->thumbnail进行了迭代，最后我使用|删除了最后的rtrim()

您可以使用此示例：

<?php

$json_output = '{"apiVersion":"2.1","data":{"id":"PL3n6kxxrIGdat31ZIf_7wlqtT3I20OqLL","author":"Tutorial top","title":"دورة سيو للمبتدئين [ali baba]","description":"","thumbnail":{"sqDefault":"https://i.ytimg.com/vi/XIhVZqCVqhs/default.jpg","hqDefault":"https://i.ytimg.com/vi/XIhVZqCVqhs/hqdefault.jpg"},"content":{"5":"http://www.youtube.com/p/PL3n6kxxrIGdat31ZIf_7wlqtT3I20OqLL"},"totalItems":31,"startIndex":1,"itemsPerPage":1,"items":[{"id":"PLH_kL5FgJPmdcYTGqaMXFsVJJ-pbR_YyiC1Y73R1tfYY","position":1,"author":"Tutorial top","video":{"id":"Kw8m5S2OhPs","uploaded":"2013-11-10T16:04:28.000Z","updated":"2014-02-18T17:59:36.000Z","uploader":"vkd-nAV91SLMCYNBKGJmsA","category":"People","title":"Beginners SEO Tutorial Course   Intro","description":"","thumbnail":
{"sqDefault":"https://i.ytimg.com/vi/Kw8m5S2OhPs/default.jpg","hqDefault":"https://i.ytimg.com/vi/Kw8m5S2OhPs/hqdefault.jpg"},"player":{"default":"https://www.youtube.com/watch?
v=Kw8m5S2OhPs&feature=youtube_gdata_player","mobile":"https://m.youtube.com/details?v=Kw8m5S2OhPs"},"content":{"5":"https://www.youtube.com/v/Kw8m5S2OhPs?version=3&f=playlists&app=youtube_gdata","1":"rtsp://r8---sn-4g57kues.c.youtube.com/CiULENy73wIaHAn7hI4t5SYPKxMYDSANFEgGUglwbGF5bGlzdHMM/0/0/0/video.3gp","6":"rtsp://r8---sn-
4g57kues.c.youtube.com/CiULENy73wIaHAn7hI4t5SYPKxMYESARFEgGUglwbGF5bGlzdHMM/0/0/0/video.3gp"},"duration":413,"aspectRatio":"widescreen","rating":5.0,"likeCount":"1","ratingCount":1,"viewCount":283,"favoriteCount":0,"commentCount":0,"accessControl":
{"comment":"allowed","commentVote":"allowed","videoRespond":"moderated","rate":"allowed","embed":"allowed","list":"allowed",
    "autoPlay":"allowed","syndicate":"allowed"}}}]}}';
 /*
  * If you want use the URL remove the comments
 */   
//$json_output = file_get_contents("https://gdata.youtube.com/feeds/api/playlists/PL3n6kxxrIGdat31ZIf_7wlqtT3I20OqLL?v=2&alt=jsonc");

    $json = json_decode($json_output);
    $string = '';

    foreach($json->data->items[0]->video->thumbnail as $day) {


  $string .= $day . "|";
}

echo rtrim($string, '|');

输出：

https://i.ytimg.com/vi/Kw8m5S2OhPs/default.jpg|https://i.ytimg.com/vi/Kw8m5S2OhPs/hqdefault.jpg

Answer 4

尝试从json_decode()

中删除true

如何使用PHP显示Json数据？

4 个答案: