这是我的SQL查询:
SELECT (
SELECT COUNT(appointment_doctor) FROM appointment
JOIN doctor ON appointment.appointment_doctor = doctor.doctor_id
WHERE appointment_doctor = doctor_id
) * doctor_payment_rate AS fees FROM doctor
JOIN doctor_payment ON doctor.doctor_id=doctor_payment.doctor_payment_doctor
结果:
费用500 1000 615 11615 1160 615 1610 285 660 220 3835 215 615 555 555 1065 1110 620 445 220 660 625 60 1715 615 10 115 615 60 625 60 330 615 625 720 625 615 670 615 500 615 500
我希望所有这些值的总和为total_fee
。
答案 0 :(得分:0)
select
sum(select
count(appointment_doctor)
from
appointment
join
doctor
on appointment.appointment_doctor= doctor.doctor_id
where
appointment_doctor=doctor_id)*doctor_payment_rate as 'Total fee'
from
doctor
join
doctor_payment
on doctor.doctor_id=doctor_payment.doctor_payment_doctor
答案 1 :(得分:0)
尝试此查询:
SELECT SUM (
(SELECT COUNT(appointment_doctor) FROM appointment
JOIN doctor ON appointment.appointment_doctor = doctor.doctor_id
WHERE appointment_doctor = doctor_id) * doctor_payment_rate))
AS total_fee
FROM doctor
JOIN doctor_payment
ON doctor.doctor_id=doctor_payment.doctor_payment_doctor
答案 2 :(得分:0)
使用mysql sum函数SUM()函数返回数值列的总和
SELECT SUM (
SELECT (
SELECT COUNT(appointment_doctor) FROM appointment
JOIN doctor ON appointment.appointment_doctor = doctor.doctor_id
WHERE appointment_doctor = doctor_id
)