动态更新D3树形图数据源

时间:2015-04-09 21:42:38

标签: d3.js treemap

我想我在这里错过了一些非常明显的东西。基本上我要做的是创建一个树形图,按钮点击将转到服务器并检索下一级到树图...这是必要的,因为树图结构太大,需要太长时间来计算所以跳一个一次一级是我们唯一的选择。

[注意IE用户,在此示例中,树形图节点名称似乎不起作用。尝试使用Chrome]

http://plnkr.co/edit/simVGU

此代码几乎完全取自

http://bost.ocks.org/mike/treemap/

我正在使用vizData1.json作为“第一”级别,并且在鼠标单击时我使用vizData2.json作为“第二”级别。你可以看到两者最终重叠。我试过svg.exit()以及svg.clear()没有任何运气。

我还应该注意,我已经尝试过这篇文章中的粘性(错误)建议

Does the d3 treemap layout get cached when a root node is passed to it?

更新: 为了继续寻找,我找到了一个成功地将新节点添加到现有树形图的示例。但是我无法适应这种逻辑,因为我尝试适应这种逻辑的树形图已被Michael Bostock大量定制 - @mbostock以允许顶部的漂亮的痕迹路径条。

可以证明附加到现有树形图节点的代码片段: http://jsfiddle.net/WB5jh/3/

另外,Stackoverflow强迫我发布代码,因为我正在链接到plnkr所以我把我的script.js转储给那些不想与plunker交互的人

$(function() {
var margin = { top: 20, right: 0, bottom: 0, left: 0 },
    width = 960,
    height = 500,
    formatNumber = d3.format(",d"),
    transitioning;

var x = d3.scale.linear()
    .domain([0, width])
    .range([0, width]);

var y = d3.scale.linear()
    .domain([0, height])
    .range([0, height]);

var treemap = d3.layout.treemap()
    .children(function (d, depth) { return depth ? null : d._children; })
    .sort(function (a, b) { return a.value - b.value; })
    .ratio(height / width * 0.5 * (1 + Math.sqrt(5)))
    .round(false)
    .sticky(false);

var svg = d3.select("#treemap")
    .append("svg")
        .attr("width", width + margin.left + margin.right)
        .attr("height", height + margin.bottom + margin.top)
        .style("margin-left", -margin.left + "px")
        .style("margin.right", -margin.right + "px")
    .append("g")
        .attr("transform", "translate(" + margin.left + "," + margin.top + ")")
        .style("shape-rendering", "crispEdges");

var grandparent = svg.append("g")
    .attr("class", "grandparent");

grandparent.append("rect")
    .attr("y", -margin.top)
    .attr("width", width)
    .attr("height", margin.top);

grandparent.append("text")
    .attr("x", 6)
    .attr("y", 6 - margin.top)
    .attr("dy", ".75em");

d3.json("vizData1.json", function (root) {
    initialize(root);
    accumulate(root);
    layout(root);
    display(root);
});

function initialize(root) {
    root.x = root.y = 0;
    root.dx = width;
    root.dy = height;
    root.depth = 0;
}

// Aggregate the values for internal nodes. This is normally done by the
// treemap layout, but not here because of our custom implementation.
// We also take a snapshot of the original children (_children) to avoid
// the children being overwritten when when layout is computed.
function accumulate(d) {
    return (d._children = d.children)
        ? d.value = d.children.reduce(function (p, v) { return p + accumulate(v); }, 0)
        : d.value;
}

// Compute the treemap layout recursively such that each group of siblings
// uses the same size (1×1) rather than the dimensions of the parent cell.
// This optimizes the layout for the current zoom state. Note that a wrapper
// object is created for the parent node for each group of siblings so that
// the parent’s dimensions are not discarded as we recurse. Since each group
// of sibling was laid out in 1×1, we must rescale to fit using absolute
// coordinates. This lets us use a viewport to zoom.
function layout(d) {
    if (d._children) {
        treemap.nodes({ _children: d._children });
        d._children.forEach(function (c) {
            c.x = d.x + c.x * d.dx;
            c.y = d.y + c.y * d.dy;
            c.dx *= d.dx;
            c.dy *= d.dy;
            c.parent = d;
            layout(c);
        });
    }
}

function display(d) {
    console.log(d);
    grandparent
        .datum(d.parent)
        .on("click", transition)
      .select("text")
        .text(name(d));

    var g1 = svg.insert("g", ".grandparent")
        .datum(d)
        .attr("class", "depth");

    var g = g1.selectAll("g")
        .data(d._children)
      .enter().append("g");

    g.filter(function (d) { return d._children; })
        .classed("children", true)
        .on("click", transition);

    g.selectAll(".child")
        .data(function (d) { return d._children || [d]; })
      .enter().append("rect")
        .attr("class", "child")
        .call(rect);

    g.append("rect")
        .attr("class", "parent")
        .call(rect)
      .append("title")
        .text(function (d) { return formatNumber(d.value); });

    g.append("foreignObject")
        .call(rect)
        .attr("class", "foreignobj")
        .append("xhtml:div")
        .attr("dy", ".75em")
        .html(function (d) { return d.name; })
        .attr("class", "textdiv");

    function transition(d) {
        if (transitioning || !d) return;
        transitioning = true;

        d3.json("vizData2.json", function (root) {
            initialize(root);
            accumulate(root);
            layout(root);
            display(root);
        });

        var g2 = display(d),
            t1 = g1.transition().duration(750),
            t2 = g2.transition().duration(750);

        // Update the domain only after entering new elements.
        x.domain([d.x, d.x + d.dx]);
        y.domain([d.y, d.y + d.dy]);

        // Enable anti-aliasing during the transition.
        svg.style("shape-rendering", null);

        // Draw child nodes on top of parent nodes.
        svg.selectAll(".depth").sort(function (a, b) { return a.depth - b.depth; });

        // Fade-in entering text.
        g2.selectAll("text").style("fill-opacity", 0);
        g2.selectAll("foreignObject div").style("display", "none"); /*added*/

        // Transition to the new view.
        t1.selectAll("text").call(text).style("fill-opacity", 0);
        t2.selectAll("text").call(text).style("fill-opacity", 1);
        t1.selectAll("rect").call(rect);
        t2.selectAll("rect").call(rect);

        t1.selectAll(".textdiv").style("display", "none"); /* added */
        t1.selectAll(".foreignobj").call(foreign);
        t2.selectAll(".textdiv").style("display", "block"); /* added */
        t2.selectAll(".foreignobj").call(foreign); /* added */

        // Remove the old node when the transition is finished.
        t1.remove().each("end", function () {
            svg.style("shape-rendering", "crispEdges");
            transitioning = false;
        });
    }

    return g;
}

function text(text) {
    text.attr("x", function (d) { return x(d.x) + 6; })
        .attr("y", function (d) { return y(d.y) + 6; });
}

function rect(rect) {
    rect.attr("x", function (d) { return x(d.x); })
        .attr("y", function (d) { return y(d.y); })
        .attr("width", function (d) { return x(d.x + d.dx) - x(d.x); })
        .attr("height", function (d) { return y(d.y + d.dy) - y(d.y); });
}

function foreign(foreign) {  /* added */
    foreign.attr("x", function (d) { return x(d.x); })
      .attr("y", function (d) { return y(d.y); })
      .attr("width", function (d) { return x(d.x + d.dx) - x(d.x); })
      .attr("height", function (d) { return y(d.y + d.dy) - y(d.y); });
}

function name(d) {
    return d.parent
        ? name(d.parent) + "." + d.name
        : d.name;
}
});

0 个答案:

没有答案