Question

我一直在网上搜索，erno 150似乎是一个常见的问题，但我正在努力解决这个代码，有什么帮助吗？

create table players
(
email varchar(30) not null,
playerpassword varchar(30),
screenName varchar (8),
primary key (email)
);

create table scores
(
screenName varchar(8),
gameword varchar(30),
score long,
foreign key (screenName) references players(screenName)
 );

Answer 1

screenName需要是要在另一个表中用作外键的player表上的键。您只需将key (screenName)添加到players的表定义中即可。也许你甚至希望它是unique key。

Answer 2

您应该引用主键，而不是任意列。但是，我建议您使用自动递增的主键。像这样：

create table players (
    playerId int not null auto_increment primary key,
    email varchar(30) not null,
    playerpassword varchar(30),
    screenName varchar(8),
    unique (email)
);

create table scores (
    scoreId int not null auto_increment primary key
    playerId int not null,
    gameword varchar(30),
    score long,
    foreign key (playerId) references players(playerId)
);

mysql错误：代码1005无法创建表errno 150

2 个答案: