在函数Python中使用用户输入作为输入

Question

我目前在Python 3中遇到了一些问题。我已经尝试弄清楚如何使用income和pension_contribution中存储的用户输入pension()但没有任何事情发生。这些用户输入应该放在哪里以便被视为输入，以便该功能可以工作？

income = input(int("What is your annual income?"))
pension_contribution = input(int("What is your monthly pension contribution?"))

def pension(pension_contribution, income):
    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")
    else:
        print("Your annual pension contribution is R", pension_contribution * 12)

Answer 1

1）你的缩进似乎已经关闭了 2）你需要调用函数

income = input(int("What is your annual income?"))
pension_contribution = input(int("What is your monthly pension contribution?"))

def pension (pension_contribution, income):

    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")

    else:
        print("Your annual pension contribution is R", pension_contribution * 12)

pension(pension_contribution, income)

Answer 2

你可以用3种不同的方式做到这一点：

<强> 1。只需调用函数

即可

def pension (pension_contribution, income):

    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")

    else:
        print("Your annual pension contribution is R", pension_contribution * 12)

income = int(input("What is your annual income?"))
pension_contribution = int(input("What is your monthly pension contribution?")) 

pension(pension_contribution, income) #call function

<强> 2。将变量放在函数

中

def pension ():
    income = int(input("What is your annual income?"))
    pension_contribution = int(input("What is your monthly pension contribution?"))
    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")

    else:
        print("Your annual pension contribution is R", pension_contribution * 12)


pension() #still have to call function

<强> 2。全局变量（不推荐）

income = int(input("What is your annual income?"))
pension_contribution = int(input("What is your monthly pension contribution?"))

def pension ():
    global income, pension_contribution
    if pension_contribution > ((income//12) * .075):
        print ("Your pension contribution is too high. Monthly pension contributions may not exceed 7.5% of your gross monthly income")

    else:
        print("Your annual pension contribution is R", pension_contribution * 12)

pension() #still have to call function

注意每次必须实际“调用”该函数。否则程序将成功运行，但从不打扰进入该功能。