Question

我必须编写一个带有参数n的脚本，并创建一个大小为n的表，其中填充了1,2,3,4，..，n。

我现在要显示所有案例的总和。

#!bin/bash

for i in $1 do
    tab[i]=$i
    echo "$tab[i]
done

Answer 1

#!/bin/sh
if [ "$#" != 1 ]
then
  echo $0 SIZE
  exit
fi

# We can use one “for” loop to both fill the array, and calculate the sum.
for ((z=1; z<=$1; z++))
do
  # Here we are creating our array “y” and adding a new value to it, “z”
  y+=($z)
  # Here we will use “let”. This is the same as using ((x+=z)), it is a way
  # to perform arithmetic on variables. In this case we are adding “z”
  # (current array value) to the total “x”
  let x+=z
done

declare -p y x

输入

输出

declare -a y='([0]="1" [1]="2" [2]="3" [3]="4" [4]="5" [5]="6" [6]="7")'
declare -- x="28"

您可以调整输出，我只使用了declare，因此您可以看到所有内容清楚。

创建一个表并计算总和

1 个答案: