Question

PHP的新手并试图创建一个嵌套列表，可能是以草率的方式做，但考虑到特定的结构。我正在尝试检查列表结构是否与数据库值匹配。

问题：似乎无法迭代第三个foreach循环（引用数据库的循环）内的'buildValue'和'floorValue'变量（在foreach1＆amp; 2中创建）。也尝试while循环，结果相同。

是否有其他方法可以实现这一目标，或者我做错了什么/傻瓜？

$htmlArray = array();
$buildingArray = array();

$buildingArray["0"] = array("4","3","2","1","0","01","02");
$buildingArray["1"] = array("4","3","2","1","0","01","02");
$buildingArray["2"] = array("4","3","2","1","0","01","02");

    foreach ($buildingArray as $bkey => $building) 
    {
        switch ($bkey) 
        {
            case "0":
                $htmlArray[0]['building'] = "Biology";
            break;
            case "1":
                $htmlArray[1]['building'] = "Chemistry";
            break;
            case "2":
                $htmlArray[2]['building'] = "Environmental";
            break;
        }

        $buildVal = $bkey;

        foreach ($building as $fkey => $floor) 
        {
            $floorVal = $floor;

            $prepend ='Floor ';
            $title = $prepend.$floor;
            $htmlArray[$fkey]['floor'] = $title;

            // Iterate over the items results 

           //NO PROBLEM: These values (reference foreach1 & foreach2) output correct result!
            echo("build=".$buildVal." ");
            echo("floor=".$floorVal." ");

            $roomArray= array();
            $roomArray = $rooms -> fetchAll(PDO::FETCH_ASSOC);

            foreach ($roomArray as $row) 
            {
                //PROBLEM: These values (reference foreach1 & foreach2) do not iterate inside foreach 3, only output 1st building and floor!

                echo("build=".$buildVal." ");
                echo("floor=".$floorVal." ");

                //echo any results matching building and floor
                if($row["building"] == $buildVal+3 && $row["floor"] == $floorVal)
                {
                    // echo($row["room");

                }

            }

        }


    }

没有问题输出： build = 0 floor = 4 build = 0 floor = 3 build = 0 floor = 2 build = 0 floor = 1 build = 0 floor = 0 build = 0 floor = 01 build = 0 floor = 02 build = 1 floor = 4 build = 1楼= 3楼= 1楼= 2楼= 1楼= 1楼= 1楼= 0楼= 1楼= 01楼= 1楼= 02楼= 2楼= 4楼= 2楼= 3楼= 2楼= 2 build = 2 floor = 1 build = 2 floor = 0 build = 2 floor = 01 build = 2 floor = 02

问题输出： build = 0 floor = 4 build = 0 floor = 4 build = 0 floor = 4 build = 0 floor = 4 build = 0 floor = 4 build = 0 floor = 4 build = 0 floor = 4 build = 0 floor = 4

$ RoomArray输出（除了最后的空数组似乎正确）：数组（[0] =＆gt;数组（[room_id] =＆gt; 1 [房间] =＆gt; 112 [地板] =＆gt; 1 [建筑物] =＆gt; 3）[1] =＆gt;数组（[room_id] =＆gt; 2 [房间] =＆gt; 111 [楼层] =＆gt; 1 [建筑物] =＆gt; 3）[2] =＆gt;数组（[room_id] =＆gt; 3 [房间] =＆gt; 116 [楼层] =＆gt; 1 [建筑物] =＆gt; 4）[3] =＆gt;数组（[room_id] =＆gt; 4 [房间] =＆gt; 115 [楼层] =＆gt; 1 [建筑物] =＆gt; 4） [4] =＆gt;数组（[room_id] =＆gt; 5 [房间] =＆gt; 114 [floor] =＆gt; 1 [建筑物] =＆gt; 4）[5] =＆gt;数组（[room_id] =＆gt; ; 6 [room] =＆gt; 113 [floor] =＆gt; 1 [building] =＆gt; 4）[6] =＆gt;数组（[room_id] =＆gt; 7 [room] =＆gt; 110 [floor] = ＆gt; 1 [建筑物] =＆gt; 5）[7] =＆gt;数组（[room_id] =＆gt; 8 [房间] =＆gt; 109 [楼层] =＆gt; 1 [建筑物] =＆gt; 5））数组（）Array（）Array（）Array（）Array（）Array（）Array（）Array（）Array（）Array（）Array（）Array（）Array（）Array（）Array（）Array（）Array（） Array（）Array（）Array（）

也许我应该重新解释一下这个问题....上面是我的数据库（尽管数据会大得多），除了有3栋楼和6层楼，我需要一个如下的嵌套列表：

 -Building1
   -Floor1
     -Room121
 -Building2
   -Floor1
   -Floor2
     -Room221

等

Answer 1

我可以看到索引$ htmlArray变量的一些问题，但在$ roomArray进入场景后我不确定你在做什么。看看下面的代码，也许有帮助。如果不是 - 确切地告诉$ roomArray循环有什么问题，什么是$ roomArray。

编辑我更新了我的答案，检查这是否为您提供所需的输出。

    $buildingArray["0"] = array("4","3","2","1","0","01","02");
    $buildingArray["1"] = array("4","3","2","1","0","01","02");
    $buildingArray["2"] = array("4","3","2","1","0","01","02");
    # Added simple dictionary
    $btype = array("Biology","Chemistry","Environmental");
    # Prefetch all rooms.
    $roomArray= array();
    $roomArray = $rooms -> fetchAll(PDO::FETCH_ASSOC);
    #
    foreach ($buildingArray as $bkey => $building) 
    {
        # This is much nicer than case...
        $htmlArray[$bkey]['building'] = $btype[$bkey];

        foreach ($building as $fkey => $floor) 
        {
            # Two things here - first, user sprintf instead of '.'.
            # Second - You got keys owerwritten with using $fkey as the first key.
            $htmlArray[$bkey]['floor'][$fkey]['title'] = sprintf('Floor %s',$floor);
            foreach ($roomArray as $room) 
            {
                if($room['building']==($bkey+3) and $room['floor']==$fkey)
                {
                    $htmlArray[$bkey]['floor'][$fkey]['rooms'][$room['room_id']] = $room['room'];
                }
            }
        }
    }
    echo '<pre>';
    print_r($htmlArray);
    echo '</pre>';

PHP嵌套的foreach不是迭代父变量

1 个答案: