Question

当RuntimeException无法连接到服务器时，如何处理AsyncTask，因为服务器是＆＃34; down＆＃34;由于某些原因？

我尝试的是一堆catch块（没有帮助）：

        try {
            // Create Request to server and get response
            HttpGet httpget = new HttpGet(activity.getString(R.string.get_channels_lang_host));
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            downloadedString = httpclient.execute(httpget, responseHandler);
        }catch (MalformedURLException e) {
            Log.e("URL:","is a malformed URL");
            e.printStackTrace();
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
            Log.e("URL:"," UnsupportedEncodingException");
        } catch (ClientProtocolException e) {
            e.printStackTrace();
            Log.e("URL:"," ClientProtocolException");
        } catch (SocketTimeoutException e) {
            e.printStackTrace();
            Log.e("URL:"," SocketTimeoutException");
        } catch (ConnectTimeoutException e) {
            e.printStackTrace();
            Log.e("URL:"," ConnectTimeoutException");
        } catch (IOException e) {
            Log.e("URL:","IOException");
            e.printStackTrace();
        }
        if (downloadedString != null) {
            //parse request to object
            dataChannelsLangArrayList = JsonParser.getDataChannelsLang(downloadedString);
        } else {
            Toast.makeText(ActivityLoading.this, "Failed to load data. Restarting...", Toast.LENGTH_LONG).show();
            Global.restartApp(ActivityLoading.this);

        }

我仍然收到运行时错误：

04-09 11:31:29.610    3696-3719/tenkol.design.com.imbrecords E/AndroidRuntime﹕ FATAL EXCEPTION: AsyncTask #1
java.lang.RuntimeException: An error occured while executing doInBackground()
        at android.os.AsyncTask$3.done(AsyncTask.java:299)
        at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:273)
        at java.util.concurrent.FutureTask.setException(FutureTask.java:124)
        at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:307)
        at java.util.concurrent.FutureTask.run(FutureTask.java:137)
        at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230)
        at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
        at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
        at java.lang.Thread.run(Thread.java:864)
 Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
        at android.os.Handler.<init>(Handler.java:121)
        at android.widget.Toast$TN.<init>(Toast.java:322)
        at android.widget.Toast.<init>(Toast.java:91)
        at android.widget.Toast.makeText(Toast.java:238)
        at tenkol.design.com.imbrecords.Global.restartApp(Global.java:115)
        at tenkol.design.com.imbrecords.ActivityLoading$LoadingAsyncTask.getChannelsLang(ActivityLoading.java:249)
        at tenkol.design.com.imbrecords.ActivityLoading$LoadingAsyncTask.doInBackground(ActivityLoading.java:157)
        at tenkol.design.com.imbrecords.ActivityLoading$LoadingAsyncTask.doInBackground(ActivityLoading.java:141)
        at android.os.AsyncTask$2.call(AsyncTask.java:287)
        at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
            at java.util.concurrent.FutureTask.run(FutureTask.java:137)
            at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230)
            at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
            at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
            at java.lang.Thread.run(Thread.java:864)

我最感兴趣的是两个案例：

当服务器根本没有响应时;
当请求的时间花费太大时（即互联网速度慢）。

处理这些问题的正确方法是什么？

Answer 1

Can't create handler inside thread that has not called Looper.prepare()

好吧，你已经创建了一个Handler，但它所链接的线程没有任何消息队列来发布内容。

尝试使用链接到主线程的处理程序new Handler(Looper.getMainLooper())。

然后你可以在它上面张贴Runnable来显示祝酒词。

但严重的是，为什么不收集异常和结果并在onPostExecute()中处理所有内容？

Public class Result<T>{
  public T data;
  public Exception exception;
  public String message;
}

处理＆＃34;服务器没有响应＆＃34; AsyncTask中的异常

1 个答案: