Question

我正在寻找从注册为ABC的子类的类的实例调用抽象基类'方法的正确方法。这是一些非常基本的测试代码，首先要弄清楚如何使这项工作。这是我目前所在的地方：

from abc import ABCMeta

# Dog class
class Dog(object):
    def speak(self):
        pass
    def move(self):
        pass

# Barking behaviors
class Bark(object):
    __metaclass__ = ABCMeta
    def speak(self):
        print "bark bark bark"

class Howl(object):
    __metaclass__ = ABCMeta
    def speak(self):
        print "ahwoooooo"

# Movement behaviors
class Run(object):
    __metaclass__ = ABCMeta
    def move(self):
        print "I'm running"

class Walk(object):
    __metaclass__ = ABCMeta
    def move(self):
        print "I'm walking"


# Dog implementations
class Beagle(Dog):
    pass
Howl.register(Beagle)
Run.register(Beagle)

nora = Beagle()
nora.speak() # THIS IS THE ISSUE: Calls speak() from original Dog class
nora.move()  # Need to call move() from registered ABC

# Test to be sure .register() was used properly
assert isinstance(nora, Howl)

虽然这种方法似乎过度涉及改变两种Dog方法，但我希望能够灵活地将行为分配给未知数量的实例。我希望能够在不知道实际行为的情况下调用speak（）和move（）。我也喜欢这种方法，因为我能够轻松删除或更改类的注册行为，而无需更改任何现有代码。

代码当前读取的方式nora.speak（）和nora.move（）调用从Dog到Beagle的继承方法，它只包含pass。

我很感激，如果有人对我在这一点上需要做什么有所了解，以使注册行为的方法可以调用，或者我的方法完全有缺陷。

Answer 1

这是我的尝试（可能不是最狡猾的方式，但接近你的帖子）：

class Animals(object):
    def speak(self):
        return self.speak_action

    def swim(self):
        return self.swim_action

    def move(self):
        return self.move_action


class Dog(Animals):
    @property
    def speak_action(self):
        return "bark bark bark"

    @property
    def move_action(self):
        return "I'm Running"


class Beagle(Dog):
    @property
    def speak_action(self):
        return "ahwoooooo"


class Duck(Animals):
    @property
    def swim_action(self):
        return "Im floating"

    @property
    def speak_action(self):
        return "Quack!!"

    @property
    def move_action(self):
        return "I Fly!"

class Mallard(Duck):
    @property
    def speak_action(self):
        return "I'm Flying higher"

（最好让异常冒泡）

In [825]: d = Dog()

In [826]: d.speak()
Out[826]: 'bark bark bark'

In [827]: d.move()
Out[827]: "I'm Running"

In [828]: d.swim()
---------------------------------------------------------------------------
AttributeError                            Traceback (most recent call last)
<ipython-input-828-c6d2ef2b464d> in <module>()
----> 1 d.swim()

.stuff/python/git_py/help_so.py in swim(self)
      4
      5     def swim(self):
----> 6         return self.swim_action
      7
      8     def move(self):

AttributeError: 'Dog' object has no attribute 'swim_action'

您可以选择要委派的内容：

In [830]: b = Beagle()

In [831]: b.speak()
Out[831]: 'ahwoooooo'

In [832]: b.move()
Out[832]: "I'm Running"

In [833]: b.swim()
---------------------------------------------------------------------------
AttributeError                            Traceback (most recent call last)
<ipython-input-833-9c7b1a0c0dca> in <module>()
----> 1 b.swim()

/stuff/python/git_py/help_so.py in swim(self)
      4
      5     def swim(self):
----> 6         return self.swim_action
      7
      8     def move(self):

AttributeError: 'Beagle' object has no attribute 'swim_action'

创造具有更多技能的其他动物：

In [849]: dd = Duck()

In [850]: dd.speak()
Out[850]: 'Quack!!'

In [851]: dd.move()
Out[851]: 'I Fly!'

In [852]: dd.swim()
Out[852]: 'Im floating'

您可以将特定内容，甚至默认值，特定内容发送到主类，并且可以根据需要进行扩展。

Python 2.7 - 调用抽象基类＆＃39;来自实例的方法

1 个答案: