Question

我想为每个项目和事件的排名（1-5）创建一个计数器。

例如，结构是[＆＃34; DATE＆＃34;，＆＃34; PRODUCT＆＃34;，＆＃34; RANKING＆＃34;]

[["1/1/15", "Product 1", "4"], ["1/1/15", "Product 1", "4"],       
 ["2/2/15", "Product 1", "1"], ["1/1/15", "Product 2", "1"], 
 ["1/1/15", "Product 2", "1"], ["3/1/15", "Product 2", "1"]]

想要的输出是

 Date: 1/1/15, Product: 1, Ranking: 4, Seen: 2
 Date: 2/2/15, Product: 1, Ranking: 1, Seen: 1 
 Date: 1/1/15, Product: 2, Ranking: 1, Seen: 2
 Date: 3/1/15, Product: 2, Ranking: 1, Seen: 1

我想制作每个日期的计数器，每个产品与排名分开。

    cc = Counter((rank, week) for rank, week in date_array)

我已经尝试过，但这只能作为日期的计数器，但我想采用不同的产品。

我该怎么做？它会是嵌套计数器吗？最后，我想将此信息写入CSV。

Answer 1

与之前提供的模式相同，将嵌套列表转换为元组，这里是通用表单，无需解压缩：

c = Counter(tuple(i) for i in data)
for k, v in c.items():
    print("Date: {}, Product: {}, Ranking: {}, Seen: {}".format(*k, v))

Answer 2

从您给定的输出中，它看起来就像您要尝试获取一个计算整个元组的Counter对象。这简直太容易了。

from collections import Counter

data = [["1/1/15", "Product 1", "4"], ["1/1/15", "Product 1", "4"],       
        ["2/2/15", "Product 1", "1"], ["1/1/15", "Product 2", "1"], 
        ["1/1/15", "Product 2", "1"], ["3/1/15", "Product 2", "1"]]

cc = Counter(map(tuple, data))

for grp,seen in cc.items():
    date, product, ranking = grp
    product = product.split()[-1] # grab just the product number
                                  # consider changing this in your data model
    ordering = [date, product, ranking, seen]
    print("Date: {}, Product: {}, Ranking: {}, Seen: {}".format(*ordering))

每个项目的柜台内的Python计数器？

2 个答案: