我在列中有以下数据,如何查询其中的值。
<deliveryPart notificationId="12345">
<message address="email@email.com" content="multipart/alternative" domain="email.com" format="0" id="159436637" recipient-id="098765" targetCode="__MAIN__">
<custom>
<recipient Nickname="mynickname" id="54321" />
<targetData Incident_Id="1509403" reference_nb="0000-0000" />
</custom>
</message>
</deliveryPart>
我快速去了,但我以前从未做过,而且时间不长。
select top 10 *
from [db].[db].[table]
where mData.value('(deliveryPart/message/recipient-id)[1]','varchar(max)') like '098765'
我收到以下错误
Msg 4121,Level 16,State 1,Line 1
找不到列&#34; mData&#34;或用户定义的函数或聚合&#34; mData.value&#34;,或名称不明确。
更新
我使用以下代码来获取xml值并且它可以正常工作
SELECT TOP 1000 B1.[mData].value('(deliveryPart/message/@id)[1]', 'NVARCHAR(MAX)') AS 'MessageID', B1.[mData].value('(deliveryPart/message/@address)[1]', 'NVARCHAR(MAX)') AS 'Address'
FROM (SELECT CAST(mData as XML) as xmlData FROM [dbo].[db].[table]) B0
CROSS APPLY xmlData.nodes('/') B1 (mData)
WHERE B1.[mData].value('(deliveryPart/message/@address)[1]', 'NVARCHAR(MAX)') LIKE '%@%'
它返回ntext字段中的xml值存储就好了。
180646774 email1@email.com
159436627 test2@hotmail.com
159436637 test3@hotmail.com
但是,我需要从mData列外部获取值,并且不允许我这样做。
答案 0 :(得分:1)
您需要将@recipient-id
用作XML 属性 - 而不是XML元素:
<message address="email@email.com" content="multipart/alternative"
domain="email.com" format="0" id="159436637"
recipient-id="098765" targetCode="__MAIN__">
************ this is an *attribute* - use the `@` to select it!
代码:
select top 10 *
from [db].[db].[table]
where mData.value('(deliveryPart/message/@recipient-id)[1]', 'varchar(max)') like '098765'