Question

给定一个字符串数组，返回包含其所有最长字符串的另一个数组。

For (String [] x = {"serm", "aa", "sazi", "vcd", "aba","kart"};)

输出

{"serm", "sazi" , "kart"}.

以下代码错误，我该怎么做才能修复它。

public class Tester {

    public static void main(String[] args) {
        Tester all = new Tester();
        String [] x = {"serm", "aa", "sazi", "vcd", "aba","kart"};
        String [] y = all.allLongestStrings(x);
        System.out.println(y);


    }

    String[] allLongestStrings(String[] input) {

        ArrayList<String> answer = new ArrayList<String>(
                Arrays.asList(input[0]));
        for (int i = 1; i < input.length; i++) {
            if (input[i].length() == answer.get(0).length()) {
                answer.add(input[i]);
            }
            if (input[i].length() > answer.get(0).length()) {
                answer.add(input[i]);
            }
        }
        return answer.toArray(new String[0]);
    }
}

Answer 1

我会给你解决方案，但作为功课，它将只是sudo代码您的解决方案的问题是，您没有找到最长的字符串，但字符串大小相同或大于第一个元素的大小

let helper = []
let maxLength = 0;
for each string in array
if (len(string) >maxLength){
     maxLength = len(string);
     clear(helper)
}
if (len(string) == maxLength)
      helper.add(string)
}
return helper;

Java数组我需要你的想法

1 个答案: