我已经设置了gulp,以便在修改gulpfile时重新加载。这个基本过程正在发挥作用,但由于某种原因,旧任务似乎没有被正确终止。
var gulp = require('gulp');
var less = require('gulp-less');
var spawn = require('child_process').spawn;
gulp.task('default', function(){
var p;
if(p)
p.kill();
p = spawn('gulp', ['watch'], {stdio: 'inherit'});
});
gulp.task('watch', ['styles', 'watch-styles', 'watch-gulp']);
gulp.task('styles', function(){
return gulp.src('./**/*.less')
.pipe(less())
.pipe(gulp.dest('./'))
});
gulp.task('watch-styles', ['styles'], function(){
gulp.watch('./**/*.less', ['styles']);
});
gulp.task('watch-gulp', ['styles'], function(){
gulp.watch('./gulpfile.js', ['default']);
});
这是一个演示问题的基本gulp文件。当我调整gulpfile以使其重新加载时,我会在控制台中收到它:
[11:21:02] Starting 'default'...
[11:21:02] Finished 'default' after 5.25 ms
[11:21:02] Using gulpfile ~/repo/gulp-reload/gulpfile.js
[11:21:02] Starting 'styles'...
[11:21:02] Finished 'styles' after 34 ms
[11:21:02] Starting 'watch-styles'...
[11:21:03] Finished 'watch-styles' after 669 ms
[11:21:03] Starting 'watch-gulp'...
[11:21:03] Finished 'watch-gulp' after 1.83 ms
[11:21:03] Starting 'watch'...
[11:21:03] Finished 'watch' after 2.92 μs
然后修改目录中的less文件会产生此输出
[11:21:24] Starting 'styles'...
[11:21:24] Finished 'styles' after 8.95 ms
[11:21:24] Starting 'styles'...
[11:21:24] Finished 'styles' after 2.92 ms
每次后续重启似乎都会导致对样式的额外调用,就像老观察者仍在那里一样。
我也在这个示例项目中创建了一个小repo on Github。
答案 0 :(得分:0)
在此任务中:
gulp.task('default', function(){
var p;
if(p)
p.kill();
p = spawn('gulp', ['watch'], {stdio: 'inherit'});
});
永远不会定义p,因为在调用该函数时总是会创建一个新变量。此外,您没有指向您想要杀死的进程的指针。更安全的方法是手动结束所有其他观察者:
gulp.task('watch-styles', ['styles'], function(){
var watcher = gulp.watch('./**/*.less', ['styles']);
watchers.push(watcher);
});
gulp.task('watch-gulp', ['styles'], function(){
var watcher = gulp.watch('./gulpfile.js', ['default']);
watchers.push(watcher);
watcher.on('change', function(){
watchers.forEach(function(el){
el.end();
})
})
});