Question

我想按两个数据库值排序结果： rating_full ，然后是 rating_count

目前，我按最高 rating_full。订购，效果很好。

$sql .= " LEFT JOIN {$wpdb->postmeta} rating ON ({$wpdb->posts}.ID = rating.post_id AND rating.meta_key IN ('**rating_full**'))";
…

…

$sql = "cast(rating.meta_value as decimal(10,2)) {$order}";
……

第一行代码是 SELECT 语句的一部分，检索 rating_full 部分

第二行代码是 ORDER B Y部分，目前只使用 rating_count

据我所知，第二行代码中提到的 rating.meta_value 是 rating_full值

我正在尝试将其设为 ORDER BY rating_full ， rating_count 我不知道如何修改第一行以便我可以实现此目的。

由于

完整代码：

// Sorting
add_filter('posts_join', 'directorySortingJoin',10,2);
function directorySortingJoin($join, $query) {
global $wpdb, $aThemeOptions;
if ($query->is_main_query() && !$query->is_admin &&   ((isset($_GET['dir-search'])) || (isset($query->query_vars["a-dir-item-category"])) || (isset($query->query_vars["a-dir-item-location"])))) {
$sql = "";
 // default ordering
 $orderby = (isset($aThemeOptions->directory->defaultOrderby)) ? $aThemeOptions->directory->defaultOrderby : 'post_date';
 // get from get parameters
 if (!empty($_GET['orderby'])) {
    $orderby = $_GET['orderby'];
}
 if ($orderby == 'rating') {
    **$sql .= " LEFT JOIN {$wpdb->postmeta} rating ON   ({$wpdb->posts}.ID =  rating.post_id AND rating.meta_key IN ('rating_full'))";**

    //$sql .= " LEFT JOIN {$wpdb->postmeta} rating ON (wp_posts.ID = rating.post_id AND rating.meta_key IN ('rating_full')) LEFT JOIN {$wpdb->postmeta} count ON ({$wpdb->posts} = count.post_id AND count.meta_key IN  ('rating_count'))";


 }
 if ($orderby == 'packages') {
    directorySaveUserPackagesToDb();
    $sql .= " LEFT JOIN {$wpdb->usermeta} packages ON ({$wpdb->posts}.post_author = packages.user_id AND packages.meta_key IN ('dir_package'))";
}
 if (isset($aThemeOptions->directory->showFeaturedItemsFirst)) {
    $sql .= " LEFT JOIN {$wpdb->postmeta} featured ON ({$wpdb->posts}.ID =  featured.post_id AND featured.meta_key IN ('dir_featured'))";
 }
$join .= $sql;
//echo $join;
 }
return $join;

 }
   add_filter('posts_orderby', 'directorySortingOrderby',10,2);
   function directorySortingOrderby($orderby, $query) {
   global $wpdb, $aThemeOptions;
   if ($query->is_main_query() && !$query->is_admin && ((isset($_GET['dir-search'])) || (isset($query->query_vars["a-dir-item-category"])) || (isset($query->query_vars["a-dir-item-location"])))) {
  $sql = "";
  // default ordering
  $orderby = (isset($aThemeOptions->directory->defaultOrderby)) ? $aThemeOptions->directory->defaultOrderby : 'post_date';
$order = (isset($aThemeOptions->directory->defaultOrder)) ?   $aThemeOptions->directory->defaultOrder : 'DESC';
   // get from get parameters
    if (!empty($_GET['orderby'])) {
    $orderby = $_GET['orderby'];
   }
 if (!empty($_GET['order'])) {
    $order = $_GET['order'];
 }
if ($orderby == 'rating') {
     if (isset($aThemeOptions->directory->showFeaturedItemsFirst)) {
        $sql = "featured.meta_value DESC, convert(rating.meta_value, decimal) {$order}";
     } else {
         //$sql = "convert(rating.meta_value, decimal)    {$order}";

        **$sql = "cast(rating.meta_value as   decimal(10,2)) {$order}";**
        //$sql = "cast(rating.meta_value as decimal(10,2)) {$order}, count.meta_value {$order}";

    }
 } else if ($orderby == 'packages') {
    if (isset($aThemeOptions->directory->showFeaturedItemsFirst)) {
        $sql = "featured.meta_value DESC, packages.meta_value {$order}";
    } else {
        $sql = "packages.meta_value {$order}";
    }
} else {
    if (isset($aThemeOptions->directory->showFeaturedItemsFirst)) {
        $sql = "featured.meta_value DESC, {$wpdb->posts}.{$orderby}   {$order}";
    }
  }
   $orderby = $sql;
   //echo $orderby;
 }
 return $orderby;
 }
// Save directory packages for sorting
function directorySaveUserPackagesToDb() {
$users = get_users();
// capabilities list
$roles = array(
   'administrator' => 10,
   'directory_5' => 9,
'directory_4' => 8,
'directory_3' => 7,
'directory_2' => 6,
'directory_1' => 5,
'editor' => 4,
'author' => 3,
'contributor' => 2,
'subscriber' => 1
);
 foreach ($users as $user) {
  if (isset($user->roles[0])) {
    if (array_key_exists($user->roles[0], $roles)) {
        update_user_meta($user->ID, 'dir_package',    $roles[$user- >roles[0]]);
    } else {
        update_user_meta($user->ID, 'dir_package',   0);
    }
   }
 }
  }

Answer 1

这是我有错别字的解决方案

$ sql。=＆＃34; LEFT JOIN {$ wpdb-＆gt; postmeta}评分为ON（{$ wpdb-＆gt; posts} .ID = rating.post_id AND rating.meta_key IN（＆＃39; rating_full＆＃39;））LEFT JOIN {$ wpdb-＆gt ; postmeta}指望ON（{$ wpdb-＆gt; posts} .ID = count.post_id AND count.meta_key IN（＆＃39; rating_count＆＃39;））＆＃34 ;;

$ sql =＆＃34; cast（rating.meta_value as decimal（10,2））{$ order}，cast（count.meta_value as decimal（10,2））{$ order}＆＃34 ;;

棘手的查询：嵌套按两个值排序

1 个答案: