Question

我的工作人员begin rescue方法中有perform个阻止

begin
  HTTParty.get(url)
rescue
  ## call failed for some reason, log and stop performing
  break
end
## do more stuff here with the result of the call if it didn't fail
## this can fail too so a further
  begin
    ##would be cumbersome
  rescue
  end

然而我得到Invalid break (SyntaxError)

还有另一种方法告诉sidekiq这项工作基本上已经完成了吗？我不想让它重试，而是完全退出。

Answer 1

回来：

begin
  HTTParty.get(url)
rescue => e
  logger.warn(e.message)
  return
end

Answer 2

你不需要休息。如果begin中的代码失败，则执行将暂停，并执行rescue块内的内容。要静默忽略并返回，只需将救援内容留空即可。

def perform
  begin
    HTTParty.get(url)
  rescue
    ## call failed for some reason, log and stop performing
  end
end

您还可以缩短方法

def perform
  HTTParty.get(url)
rescue
  ## call failed for some reason, log and stop performing
end

您可能只想明确拯救某些例外情况。我不确定你想要拯救什么（这取决于HTTParty可以提出什么）。

def perform
  HTTParty.get(url)
rescue WhateverError
  ## call failed for some reason, log and stop performing
end

这是一个例子

def perform
  HTTParty.get(url)
rescue WhateverError => e
  Rails.logger.error "Kaboom! #{e.message}"
end

停止sidekiq工人执行方法

2 个答案: