Question

#! /usr/bin/python -tt
import os
def searchFile(path1,ext1,fileName1):
    pathList = []
    for root, dirs, files in os.walk(path1):
        for file in files:
            if file.endswith(ext1):
               pathList.append(os.path.join(root,file))
    print "-----The file is present under the below path------\n"
    for ele in pathList:
        if fileName1 in ele:
            print ele
def main():
    path = raw_input("Please enter the path you wish to spider. Also make sure that the files/subfolders have the correct permissions.\n")
    ext = raw_input("Enter the extension you wish to search/ find. Eg: For class files enter .class / For text file enter .txt \n")
    fileName = raw_input("Enter the filename without extension. Eg For example.class, input only 'example'\n")
    searchFile(path,ext,fileName)
if __name__ == '__main__':
main()

使用普通的文件/子文件夹，它可以正确获取路径/文件名，但是当通过'jars'进行搜索时，python脚本不会返回任何内容。如何让上面的脚本扫描Jars？

Answer 1

Jars类似于Zip档案。要扫描jar文件，您可以使用pyhton模块zipfile获取其内容列表，或者您甚至可以阅读内容。您可以使用Zipfile.namelist（）方法获取jar中的内容列表，然后使用此列表检查您要搜索的文件是否存在。下面是一个示例代码，它获取jar中存在的文件列表。

import zipfile
archive = zipfile.ZipFile('<path to jar file>/test.jar', 'r')
list = archive.namelist()

如果你在comaand line或terminal中运行它，你会得到如下输出：

['file1.class'，'file2.class']

其中file1和file2是我在jar文件中的两个.class文件

Answer 2

#! /usr/bin/python -tt
import os
import time
import zipfile
def searchFile(path1,ext1,fileName1):
    pathList1 = []
    list = []
    for root, dirs, files in os.walk(path1):
        for file in files:
            if file.endswith(ext1):
               pathList1.append(os.path.join(root,file))
    print "-----All The jar files present got collected------\n"
    for ele in pathList1:
        archive = zipfile.ZipFile(ele,'r')
        list1 = archive.namelist()
        newList1 = [ele+item for item in list1]
        list = list + newList1

    print "-----Jar files unzip done------\n"
    print "----- Now fetching filename along with the path------\n"
    for ele in list:
    if fileName1 in ele:
        print ele
def main():
    path = raw_input("Please enter the path you wish to spider. Also make sure that the files/subfolders have the correct permissions.\n")
    fileName = raw_input("Enter the filename '\n")
    fileName = "/" + fileName
    searchFile(path,".jar",fileName)
if __name__ == '__main__':
    main()

@bonney @heinst ..为你们干杯，我终于写了上面的剧本来做最后的工作。

Answer 3

文件名：searchForFiles.py

import os, zipfile, glob, sys

def main():
    searchFile = sys.argv[1] #class file to search for, sent from batch file below (optional, see batch file code in second code section)
    listOfFilesInJar = []
    for file in glob.glob("*.jar"):
        archive = zipfile.ZipFile(file, 'r')
        for x in archive.namelist():
            if str(searchFile) in str(x):
                listOfFilesInJar.append(file)

    for something in listOfFilesInJar:
        print("location of "+str(searchFile)+": ",something)

if __name__ == "__main__":
    sys.exit(main())

您可以通过使用以下文本制作.bat文件来轻松运行此文件（将“ AddWorkflows.class”替换为要搜索的文件）：

（文件：CallSearchForFiles.bat）

@echo off
python -B -c "import searchForFiles;x=searchForFiles.main();" AddWorkflows.class
pause

您可以双击CallSearchForFiles.bat轻松运行它。

我正在尝试使用Python在jar文件中搜索'.class'文件

3 个答案: