Question

我有两张桌子：

FirstTable
SecondTable

FirstTable包含这些列

sales_ID varchar(250)
product_ID int

SecondTable包含这些列

sales_ID varchar(250)
product_ID int
CreateDate datetime

如果FirstTable的{{1}}和sales_ID与product_ID的{{1}}和SecondTable以及sales_Id匹配} product_ID是07.04.2015，我需要删除SecondTable

中的行

我试过这样：

CreatedDate

然而，它会删除所有行，并且根据我的需要，它也不正确（不工作）查询。

如果product_ID等于product_ID且sales_ID等于sales_ID且CreatedDate等于SecondTable的07.04.2015，我如何删除重复的行？

希望你能理解我的坏英语

感谢。

Answer 1

那是因为它纯粹检查第二个表中的销售ID和产品ID的存在，而不是在同一记录中。

试试例子

Delete T2
FROM firsttable AS T1
INNER JOIN secondtable T2
on T1.sales_id = T2.sales_id
AND T1.product_id = T2.product_id
WHERE T1.CreatedDate = '20150407'  -- assuming you mean 7th April?

Answer 2

DELETE 
  FROM SecondTable t2
  JOIN FirstTable t1
    ON t1.sales_ID = t2.sales_ID
   AND t1.product_ID = t2.product_ID
   AND t1.CreatedDate = '2015-07-04'

Answer 3

试试这个：

delete from secondtable
from secondTable st
inner join firstTable ft on st.sales_id = ft.sales_id
    and st.product_id = ft.product_id
    and st.CreatedDate = '2015-07-04'

请注意，您可能希望在事务中包含上述内容，以确保不删除不需要的记录 - 或将语句转换为选择：

select st.*
from secondTable st
inner join firstTable ft on st.sales_id = ft.sales_id
    and st.product_id = ft.product_id
    and st.CreatedDate = '2015-07-04'

t sql delete重复2个表中的行

3 个答案: