IV

Question

在客户端（移动设备），我使用CryptoJS加密用户密码：

var lib_crypt = require('aes');

$.loginButton.addEventListener('click', function(e){

var key = lib_crypt.CryptoJS.enc.Hex.parse('bcb04b7e103a0cd8b54763051cef08bc55abe029fdebae5e1d417e2ffb2a00a3');
var iv  = lib_crypt.CryptoJS.enc.Hex.parse('101112131415161718191a1b1c1d1e1f');

var encrypted = lib_crypt.CryptoJS.AES.encrypt($.passwordInput.value, key, { iv: iv });

var password_base64 = encrypted.ciphertext.toString(lib_crypt.CryptoJS.enc.Base64); 
return password_base64; 
});

在服务器端，我想用mcrypt_decrypt解密它：

function decryptPassword($password)
{
    $key = pack('H*', "bcb04b7e103a0cd8b54763051cef08bc55abe029fdebae5e1d417e2ffb2a00a3");
    $ciphertext_dec = base64_decode($password);
    $iv_dec = "101112131415161718191a1b1c1d1e1f";

    $ciphertext_dec = substr($ciphertext_dec, 16);
    $decryptedPassword = mcrypt_decrypt(MCRYPT_RIJNDAEL_128, $key, $ciphertext_dec, MCRYPT_MODE_CBC, $iv_dec);

    return trim($decryptedPassword);
}

我使用相同的密钥和IV，我做错了什么？

Answer 1

您好，

为了达到这个目的，应该考虑使用密钥和iv，每个都有32个十六进制数字，我必须正确解决这个问题，这就是它的方式

<script src="http://crypto-js.googlecode.com/svn/tags/3.1.2/build/rollups/aes.js">
</script>
<script type="text/javascript">
//The key and iv should be 32 hex digits each, any hex digits you want, but it needs to be 32 on length each
var key = CryptoJS.enc.Hex.parse("0123456789abcdef0123456789abcdef");
var iv =  CryptoJS.enc.Hex.parse("abcdef9876543210abcdef9876543210");
/*
if you wish to have a more friendly key, you can convert letters to Hex this way:
var a = "D";
var hex_D = a.charCodeAt(0).toString(16);
just to mention,
if it were to binary, it would be:
var binary_D = a.charCodeAt(0).toString(2);
*/

var secret = "Hi, this will be seen uncrypted later on";

//crypted
var encrypted = CryptoJS.AES.encrypt(secret, key, {iv:iv});
//and the ciphertext put to base64
encrypted = encrypted.ciphertext.toString(CryptoJS.enc.Base64);    
//Assuming you have control on the server side, and know the key and iv hexes(we do),
//the encrypted var is all you need to pass through ajax,
//Let's follow with welcomed pure JS style, to reinforce one and other concept if needed
var xh = new XMLHttpRequest();
xh.open("POST", "decrypt_in_php.php", true);
xh.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xh.send("encrypted="+encodeURIComponent(encrypted));
</script>

现在在PHP中接收和解密

<?php
//Here we have the key and iv which we know, because we have just chosen them on the JS,
//the pack acts just like the parse Hex from JS

$key = pack("H*", "0123456789abcdef0123456789abcdef");
$iv =  pack("H*", "abcdef9876543210abcdef9876543210");

//Now we receive the encrypted from the post, we should decode it from base64,
$encrypted = base64_decode($_POST["encrypted"]);
$shown = mcrypt_decrypt(MCRYPT_RIJNDAEL_128, $key, $encrypted, MCRYPT_MODE_CBC, $iv);

echo $shown;
//Although the decrypted is shown, there may be needed to trim and str_replace some \r \n \x06 \x05, if there is not a better "trim" way to do it though
?>

有了这个，我们将退回＆＃34;嗨，这将在以后未加密的情况下看到＆＃34; ：）

Answer 2

以下是基于this comment的解决方案，使用了PHP中的openssl_decrypt。

JavaScript 部分（使用NodeJS为浏览器开发）—首先，将CryptoJS与npm install crypto-js一起安装，然后安装JS代码：

import aes from 'crypto-js/aes'
import encHex from 'crypto-js/enc-hex'
import padZeroPadding from 'crypto-js/pad-zeropadding'

// message to encrypt
let msg = "Hello world";

// the key and iv should be 32 hex digits each, any hex digits you want, but it needs to be 32 on length each
let key = encHex.parse("0123456789abcdef0123456789abcdef");
let iv =  encHex.parse("abcdef9876543210abcdef9876543210");

// encrypt the message
let encrypted = aes.encrypt(msg, key, {iv:iv, padding:padZeroPadding}).toString();

// and finally, send this "encrypted" string to your server

在 PHP 端，您的代码将如下所示：

// we use the same key and IV
$key = hex2bin("0123456789abcdef0123456789abcdef");
$iv =  hex2bin("abcdef9876543210abcdef9876543210");

// we receive the encrypted string from the post
$encrypted = $_POST['decrypt'];
$decrypted = openssl_decrypt($encrypted, 'AES-128-CBC', $key, OPENSSL_ZERO_PADDING, $iv);
// finally we trim to get our original string
$decrypted = trim($decrypted);

Answer 3

你双方并没有做同样的事情。

IV

你确实在CryptoJS中解析了IV，但忘记用PHP做了：

$iv_dec = pack('H*', "101112131415161718191a1b1c1d1e1f");

要解决你的IV错误，你可能会注意到前16个字节是乱码。当IV出错时就会发生这种情况。请注意，CryptoJS默认使用CBC模式，因此IV在解密期间仅对第一个块有影响。删除：

$ciphertext_dec = substr($ciphertext_dec, 16);

填充

你可能已经注意到大多数明文都不对。他们最后以一些奇怪的重复字符结尾。这是在CryptoJS中默认应用的PKCS＃7填充。你必须自己在PHP中删除填充。好的是，Maarten Bodewes为此here提供了适当的复制粘贴解决方案。

trim()可能适用于ZeroPadding，但不适用于使用类似PKCS＃7中定义的填充方案的情况。您可以完全删除trim()调用，因为它没有用，可能会导致意外的明文，因为零字节会从开头和结尾修剪空白。

使用CryptoJS加密并使用PHP解密

3 个答案:

IV

填充