Question

我正在创建一个Android应用程序，它将接受用户的前四位数字，不仅会从1-100开始逐行显示数字，还会将它们单独保存在联系人中。对于例如用户类型9179和TextView将显示从9179000000到9179000100。问题是我的代码是将单个联系人中的号码保存为个人号码。这是代码：

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    test=(TextView)findViewById(R.id.textView1);
    getit=(EditText)findViewById(R.id.editText1);
    b=(Button)findViewById(R.id.button1);

    b.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub
            StringBuilder t = new StringBuilder(); 
            String result=getit.getText().toString();
            for (int l=series; l<=100; l++) {
                t.append(result);
                t.append(String.format("%06d", l)+"\n");
                }
            test.setText(t.toString());  
            String sphone=test.getText().toString();

        /*  String result=getit.getText().toString();
            test.setText(result);  */

            ArrayList<ContentProviderOperation> ops = new ArrayList<ContentProviderOperation>();
            int rawContactInsertIndex = ops.size();

            ops.add(ContentProviderOperation.newInsert(RawContacts.CONTENT_URI)
                    .withValue(RawContacts.ACCOUNT_TYPE, null)
                    .withValue(RawContacts.ACCOUNT_NAME, null).build());

            ops.add(ContentProviderOperation
                    .newInsert(Data.CONTENT_URI)
                    .withValueBackReference(
                            ContactsContract.Data.RAW_CONTACT_ID,   rawContactInsertIndex)
                    .withValue(Data.MIMETYPE, Phone.CONTENT_ITEM_TYPE)
                    .withValue(Phone.NUMBER, sphone) // Number of the person
                    .withValue(Phone.TYPE, Phone.TYPE_MOBILE).build()); // Type of mobile number                    
            try
            {
                ContentProviderResult[] res = getContentResolver().applyBatch(ContactsContract.AUTHORITY, ops);
            }
            catch (RemoteException e)
            { 
                // error
                e.printStackTrace();
            }
            catch (OperationApplicationException e) 
            {
                // error
                e.printStackTrace();
            }
        }
    });


}
}

Answer 1

我没有检查您的ContentProviderOperation代码，但如果它正确且有效，则其余代码应如下所示。

你在for循环后只创建了1 String sphone。相反，for循环应该扩展到ContentProviderOperation对象的创建。使用此applyBatch功能，您可以一次添加多个联系人。

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub
            final String result = getit.getText().toString();
            ArrayList<ContentProviderOperation> ops = new ArrayList<ContentProviderOperation>();

            for (int l=series; l<=100; l++) {
                String sphone = result + String.format("%06d", l);

                int rawContactInsertIndex = ops.size();

                ops.add(ContentProviderOperation.newInsert(RawContacts.CONTENT_URI)
                        .withValue(RawContacts.ACCOUNT_TYPE, null)
                        .withValue(RawContacts.ACCOUNT_NAME, null).build());

                ops.add(ContentProviderOperation
                        .newInsert(Data.CONTENT_URI)
                        .withValueBackReference(
                                ContactsContract.Data.RAW_CONTACT_ID, rawContactInsertIndex)
                        .withValue(Data.MIMETYPE, Phone.CONTENT_ITEM_TYPE)
                        .withValue(Phone.NUMBER, sphone) // Number of the person
                        .withValue(Phone.TYPE, Phone.TYPE_MOBILE).build()); // Type of mobile number

            }
            try {
                ContentProviderResult[] res = getContentResolver().applyBatch(ContactsContract.AUTHORITY, ops);
            } catch (RemoteException e) {
            } catch (OperationApplicationException e) {
            }
        }

如何从textview到联系人列表显示和保存手机号码

1 个答案: