我已经使用了js来乘以但只有第一行得到乘以其他行是nt得倍。
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("form1", $con);
error_reporting(E_ALL ^ E_NOTICE);
$nam=$_REQUEST['select1'];
$row=mysql_query("select * from inv where name='$nam'");
while($row1=mysql_fetch_array($row))
{
$Name=$row1['Name'];
$Address =$row1['Address'];
$City=$row1['City'];
$Pincode=$row1['Pincode'];
$No=$row1['No'];
$Date=$row1['Date'];
$DCNo=$row1['DCNo'];
$DcDate=$row1['DcDate'];
$YourOrderNo=$row1['YourOrderNo'];
$OrderDate=$row1['OrderDate'];
$VendorCode=$row1['VendorCode'];
$SNo=$row1['SNo'];
$descofgoods=$row1['descofgoods'];
$Qty=$row1['Qty'];
$Rate=$row1['Rate'];
$Amount=$row1['Amount'];
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
<script type="text/javascript">
**function ram()
{
var q=document.getElementById('qty').value;
var r=document.getElementById('rate').value;
document.getElementById('amt').value=q*r;
}**
</script>
</head>
<body>
<form id="form1" name="form1" method="post" action="">
<table width="1315" border="0">
<script type="text/javascript">
function g()
{
form1.submit();
}
</script>
<tr>
<th>Name</th>
<th align="left"><select name="select1" onchange="g();">
<option value="" selected="selected">select</option>
<?php $row=mysql_query("select Name from inv ");
while($row1=mysql_fetch_array($row))
{ ?>
<option value="<?php echo $row1['Name'];?>"><?php echo $row1['Name'];?></option>
<?php } ?>
</select></th>
</tr>
<tr>
<th>Address</th>
<th align="left"><textarea name="Address"><?php echo $Address;?></textarea></th>
</tr>
<tr>
<th>City</th>
<th align="left"><input type="text" name="City" value='<?php echo $City;?>' /></th>
</tr>
<tr>
<th>Pincode</th>
<th align="left"><input type="text" name="Pincode" value='<?php echo $Pincode;?>'></th>
</tr>
<tr>
<th>No</th>
<th align="left"><input type="text" name="No2" value='<?php echo $No;?>' readonly="" /></th>
</tr>
<tr>
<th>Date</th>
<th align="left"><input type="text" name="Date" value='<?php echo $Date;?>' readonly="" /></th>
</tr>
<tr>
<th>DCNo</th>
<th align="left"><input type="text" name="DCNo" value='<?php echo $DCNo;?>' readonly="" /></th>
</tr>
<tr>
<th>DcDate:</th>
<th align="left"><input type="text" name="DcDate" value='<?php echo $DcDate;?>' /></th>
</tr>
<tr>
<th>YourOrderNo</th>
<th align="left"><input type="text" name="YourOrderNo" value='<?php echo $YourOrderNo;?>' readonly="" /></th>
</tr>
<tr>
<th>OrderDate</th>
<th align="left"><input type="text" name="OrderDate" value='<?php echo $OrderDate;?>' readonly="" /></th>
</tr>
<tr>
<th width="80">VendorCode</th>
<th width="1225" align="left"><input type="text" name="VendorCode" value='<?php echo $VendorCode;?>' readonly="" /></th>
</tr>
</table>
<table width="1313" border="0">
<tr>
<td width="44"> </td>
<td width="71">SNO</td>
<td width="527">DESCRIPTION</td>
<td width="214">QUANTITY</td>
<td width="214">RATE/UNIT</td>
<td width="217">AMOUNT</td>
</tr>
<?php $i=1;
$row=mysql_query("select * from inv where Name='$nam'");
while($row1=mysql_fetch_array($row))
{
$descofgoods=$row1['descofgoods'];
$Qty=$row1['Qty'];
$Rate=$row1['Rate'];
$Amount=$row1['Amount'];
?>
<tr>
<td><input type="checkbox" name="checkbox" value="checkbox" /></td>
<td><input type="text" name="No" value='<?php echo $No;?>' readonly=""/></td>
<td><input type="text" name="descofgoods" value='<?php echo $descofgoods;?>' /></td>
<td><input type="text" name="qty" maxlength="50000000" id="qty"/></td>
<td><input type="text" name="Rate" value='<?php echo $Rate;?>' id="rate" onclick="ram()";></td>
<td><input type="text" name="Amount" id="amt"/></td>
</tr>
<?php $i++;} ?>
<tr>
<th colspan="2"><a href="pp.php?msg=<?php echo $nam;?>">Print</a></th>
</tr>
</table>
<label></label>
</form>
</body>
</html>
答案 0 :(得分:3)
我没有阅读您的所有代码,但我认为问题在于您的代码ID必须是唯一的。
var q=document.getElementById('qty').value;
var r=document.getElementById('rate').value;
document.getElementById('amt').value=q*r;
javascript没有得到另一个标签,因为你有多个标签带有'qty','rate','amt',所以javascript只转换首先出现在页面上的标签,只有多个标签。< / p>
为了避免这一点,你应该确保你的每个标签都必须是独一无二的
EDITED
1]改变你的javascript函数
function ram(id)
{
var q=document.getElementById('qty_'+id).value;
var r=document.getElementById('rate_'+id).value;
document.getElementById('amt_'+id).value=q*r;
}
2]为每个标签添加后缀$ i
<td><input type="text" name="qty" maxlength="50000000" id="qty_<?PHP echo($i) ?>"/></td>
<td><input type="text" name="Rate" value='<?php echo $Rate;?>' id="rate_<?PHP echo($i) ?>" onclick="ram('<?PHP echo($i) ?>')";></td>
<td><input type="text" name="Amount" id="amt_<?PHP echo($i) ?>"/></td>
3]在onclick函数中传递行的参数
onclick="ram('<?PHP echo($i) ?>')"
答案 1 :(得分:1)
您遇到的问题是,在您有多行的情况下使用getElementById
。 Id应该是唯一的,因此在使用getElementById时它只会获得“第一次”匹配。
答案 2 :(得分:0)
尝试使用 parseInt():
document.getElementById('amt').value= parseInt(q) * parseInt(r);