鉴于WAV文件,我想打印出ChunkSize,SubChunk1Size和SubChunk2Size。
以下是我写的代码:
#include <stdio.h>
#include <stdlib.h>
struct wavFile{
char ChunkID[4]; //"RIFF", GOOD
unsigned int ChunkSize;
char Format[4]; //"WAVE", GOOD
char Subchunk1ID[4]; //"fmt", GOOD
unsigned int Subchunk1Size; //GOOD
unsigned short int AudioFormat; //GOOD
unsigned short int NumChannels; //GOOD
unsigned int SampleRate; //GOOD
unsigned int ByteRate;
unsigned int BlockAlign;
unsigned int BitsPerSample;
char SubChunk2ID[4]; //"data", prints weird symbols instead of "data"
unsigned int Subchunk2Size;
};
int main()
{
struct wavFile w;
int headerSize = sizeof(w);
FILE *fp;
fp = fopen(wavFilePathGoesHere, "r");
fread(&w, headerSize, 1, fp);
printf("ChunkSize: %d, SubChunk1Size: %d, SubChunk2Size: %d\n", w.ChunkSize, w.Subchunk1Size, w.Subchunk2Size);
//SubChunk2Size: -76154081
fclose(fp);
return 0;
}
我在结构中注释的变量为&#34; GOOD&#34;实际上给出了正确的值,所以这些都是好的。 printf语句给出负SubChunk2Size值(-76154081)。当然,这可能是对的。我不知道我在这里做错了什么。
答案 0 :(得分:2)
使用%u
而不是%d
来获取无符号整数的printf。具体见http://www.cplusplus.com/reference/cstdio/printf/
specifier Output Example
d or i Signed decimal integer 392
u Unsigned decimal integer 7235
答案 1 :(得分:2)
BlockAlign
和BitsPerSample
应该是短片。