我有一个程序,用户输入一个"地址簿"在他们可以搜索之前他们必须进入5个人。对于电话号码,它只会使用区号来保持快速。
我的问题是,在程序结束时,它要求用户搜索名称或电子邮件,然后返回它所在的索引。我希望它显示该人的实际信息。
static void Main (string[] args)
{
int size = 5;
string[] names = new string[size];
int[] Age = new int[size];
string[] address = new string[size];
int[] phone = new int[size];
string[] email = new string[size];
bool stop = false; // stop to flag for while loops to end loops
string temp;
int counter = 0;
while((stop == false) && (counter <5)) // counter can only get to 5 and both statements must be true
{
Console.WriteLine ("Enter a name or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true; // Allowing user to quit
}
else
{
names [counter] = temp; // temp value stored into names array [counter]
}
Console.WriteLine ("Enter the age or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true;
}
else
{
Age [counter] = Convert.ToInt16(temp); // converts a string to integer
}
Console.WriteLine ("Enter address or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true; // Allowing user to quit
}
else
{
address [counter] = temp;
}
Console.WriteLine ("Enter phone number or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true;
}
else
{
phone [counter] = Convert.ToInt32(temp); // converts a string to integer
}
Console.WriteLine ("Enter a email or q/Q to quit");
temp = Console.ReadLine ();
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true; // Allowing user to quit
}
else
{
email [counter] = temp;
counter = counter + 1;
}
}
for (int i = 0; i <5; i++)
{
Console.WriteLine (names [i]);
Console.WriteLine (Age [i]);
Console.WriteLine (address [i]);
Console.WriteLine (phone [i]);
Console.WriteLine (email [i]);
}
Console.WriteLine ("Enter a name or email to search or Q/q to quit");
temp = Console.ReadLine ();
stop = false;
while (stop == false)
{
if (temp == "q" || temp == "Q") {
Console.WriteLine ("Quitting");
stop = true;
}
else
{
for (int i = 0; i <5; i++)
{
if (temp == names [i] || temp == email [i]) {
Console.WriteLine ("Name is found at index {0}", i);
stop = true;
}
else
{
if (i == 5)
{
Console.WriteLine ("Value not found");
stop = true;
}
}
}
}
Console.ReadLine ();
答案 0 :(得分:1)
只需替换
Console.WriteLine ("Name is found at index {0}", i);
带
Console.WriteLine ("Person is found at index {0}. Name: {1}, Age: {2}, Address: {3}, Phone: {4}, Email: {5}", i, names[i], Age[i], address[i], phone[i], email [i]);
你应该把这个方法分解为更短的方法,因为它做了很多事情(它有很多责任),很难阅读和理解。第一步可能是将填充数据结构(输入数据)与使用它们(打印过滤数据)分开。
您可以创建名为eg的类,而不是为每个属性创建数组。 Person
成员名称,年龄,地址,电话,电子邮件和一个数组 - 一组Person
个对象。这将简化您的代码。
最好将人员保持在列表而不是数组中,因为你事先不知道用户何时点击Q)uit并停止添加新人员。如果size为10000并且用户在10个条目之后退出,则为Person对象分配9990但未使用的空格。
另外,想想如果没有输入Person的某些字段时如何处理这种情况。 (你想使用例如空字符串,或者根本不想将半填充实例添加到列表中......)。
答案 1 :(得分:0)
您应该使用名称,年龄,地址,电话号码属性的地址簿类,并且您可以使用通用列表来存储用户输入的数据。
通用列表已经有了查找方法。
答案 2 :(得分:0)
更改
if (temp == names [i] || temp == email [i]) {
Console.WriteLine ("Name is found at index {0}", i);
stop = true;
}
要
if (temp == names [i] || temp == email [i]) {
Console.WriteLine (names [i]);
Console.WriteLine (Age [i]);
Console.WriteLine (address [i]);
Console.WriteLine (phone [i]);
Console.WriteLine (email [i]);
}
在用户输入q或Q之前,我不会打扰停止。