Question

我正在尝试编写一个带有3个参数的powershell函数

Function CopyVHD ($filename, $sourcevhd, $destination)
{
    echo "filename is $filename"
    echo "source is $sourcevhd"
    echo "destination is $destination"
    # Validate that the VHD doesn't exist on remote
    if ( Test-Path "$sourcevhd\$filename" )
    {
        echo "File $filename already exists at $destination"
    }
    else 
    {
      echo "copying $sourcevhd\\$filename to $destination"
      Copy-Item $sourcevhd\$filename "$destination" -Recurse
    }

}

然后传入3个参数

CopyVHD("foo.vhd","c:\","d:\")

为什么powershell将3个参数合并为1？如果您在下面的输出中注意到，变量filename已消耗所有3个参数，而参数source和destination为空。

PS C:\Windows\system32> C:\Users\example\Documents\closed-pile.ps1
newest vhd is foo.vhd
filename is foo.vhd C:\ D:\
source is 
destination is 
copying \\foo.vhd C:\ D:\ to 
Copy-Item : Cannot find drive. A drive with the name '\foo.vhd C' does not exist.
At C:\Users\example\Documents\closed-pile.ps1:28 char:7
+       Copy-Item $sourcevhd\$filename "$destination" -Recurse
+       ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    + CategoryInfo          : ObjectNotFound: (\foo.vhd C:String) [Copy-Item], DriveNotFoundException
    + FullyQualifiedErrorId : DriveNotFound,Microsoft.PowerShell.Commands.CopyItemCommand

我尝试过不同的变量名，因为我错误地使用了保留字。我尝试过不同的空间语法。

CopyVHD ("foo.vhd","c:\","d:\")
CopyVHD("foo.vhd","c:\","d:\")
CopyVHD("foo.vhd", "c:\", "d:\")
CopyVHD( "foo.vhd", "c:\", "d:\" )

我在同一个脚本中有另一个函数，可以正确接受2个参数。为什么这个功能不起作用？

更新

我尝试了以下语法，该链接的SO问题中显示了该语法。它给出了同样的失败

CopyVHD "foo.vhd", "C:\", "D:\"

UPDATE2

也尝试用单引号

CopyVHD 'foo.vhd', 'C:\', 'D:\'

功能仍然无法识别3个参数

PS C:\Windows\system32> C:\Users\sowen\Documents\closed-pile.ps1
filename is foo.vhd C:\ D:\
source is 
destination is

Answer 1

您不必使用逗号分隔PowerShell中的参数，逗号用于显示一个参数的多个条目。

您应该调用此函数的方法是使用空格分隔参数。或者更好的是，提供参数名称。

CopyVHD A B C

或

CopyVHD -filename A -sourcevhd B -destination C >filename is a source is b destination is c

为什么powershell无法识别多个参数？

1 个答案: