Question

insert into MemberGroup (MemberId, MemberGroupId, MemberJoinDate, MemberExpiryDate)
   SELECT DISTINCT 
       TransMemberId, 404, MAX(transaction_time), 
       dateadd(yy,1,MAX(transaction_time))
   FROM 
       DataTrans 
   INNER JOIN 
       DataTransItem ON DataTransId = DataTransItemId
   LEFT JOIN 
       MemberGroup ON MemberId = DataTransItemId
   INNER JOIN 
       MemberMembership ON MemberId = MembershipId
   INNER JOIN 
       LinkedMember ON MembershipId = LinkedMemberId
   WHERE 
       membership_clubid = 1 
       AND TransMemberId IN (select LinkedMemberId from LinkedMember)
       AND TransMemberId IN (select LinkedMemberId from LinkedMember 
                             where MemberGroupId NOT IN (1, 2, 3, 4, 5))
       AND TransMemberId IN (select MemberLinkedId from LinkedMember 
                             where DataTransItemId = 2414)
   GROUP BY 
      TransMemberId

为什么这会返回以下错误，即使它在insert语句中使用了distinct，也在最后将TransMemberId分组以选择一个。

违反PRIMARY KEY约束＆＃39; PK_MembershipGroup＆＃39;。无法在对象＆＃39; dbo.MemberGroup＆＃39;中插入重复的密钥。重复键值为（FFASED487948KXWC1MH7,404）。

DataTransId
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11

TransMemberId
F123TK1TSXX7
F123TK1TSXX7
F123TK1TSXX7
KS723423CLG8LSQ
KS723423CLG8LSQ
KS723423CLG8LSQ
KS723423CLG8LSQ
KS723423CLG8LSQ
48232423KXWC1MH7
48232423KXWC1MH8
48232423KXWC1MH9
F2P3XQTTRJ44232423
F2P3XQTTRJ44232424
F2P3XQTTRJ44232425
F2P3XQTTRJ44232426
F2P3XQTTRJ44232427

DataTransItemId
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11
1.24322E+11

MembershipId
F123TK1TSXX7
F123TK1TSXX7
F123TK1TSXX7
KS723423CLG8LSQ
KS723423CLG8LSQ
KS723423CLG8LSQ
KS723423CLG8LSQ
KS723423CLG8LSQ
48232423KXWC1MH7
48232423KXWC1MH8
48232423KXWC1MH9
F2P3XQTTRJ44232423
F2P3XQTTRJ44232424
F2P3XQTTRJ44232425
F2P3XQTTRJ44232426
F2P3XQTTRJ44232427

LinkedMemberId
F123TK1TSXX7
F123TK1TSXX7
F123TK1TSXX7
KS723423CLG8LSQ
KS723423CLG8LSQ
KS723423CLG8LSQ
KS723423CLG8LSQ
KS723423CLG8LSQ
48232423KXWC1MH7
48232423KXWC1MH7
48232423KXWC1MH7
F2P3XQTTRJ44232423
F2P3XQTTRJ44232423
F2P3XQTTRJ44232423
F2P3XQTTRJ44232423
F2P3XQTTRJ44232423

MemberLinkedId
48KXWC1MH7ASGER
48KXWC1MH7ASGER
48KXWC1MH7ASGER
LKJDJX2RQ26Y7VD
LKJDJX2RQ26Y7VD
LKJDJX2RQ26Y7VD
LKJDJX2RQ26Y7VD
LKJDJX2RQ26Y7VD
F1TK1TSXX723FSDE
F1TK1TSXX723FSDE
F1TK1TSXX723FSDE
Z3VHVL846QQWER
Z3VHVL846QQWER
Z3VHVL846QQWER
Z3VHVL846QQWER
Z3VHVL846QQWER

Answer 1

我认为您的查询可以是这样的：

 insert into MemberGroup (MemberId, MemberGroupId, MemberJoinDate, MemberExpiryDate)
 (SELECT TransMemberId , 404, MAX(transaction_time), dateadd(yy,1,MAX(transaction_time))

 FROM DataTrans 
      INNER JOIN DataTransItem ON DataTransId = DataTransItemId
      LEFT JOIN MemberGroup ON MemberId = DataTransItemId
      INNER JOIN MemberMembership ON MemberId = MembershipId
      INNER JOIN LinkedMember ON MembershipId = LinkedMemberId

 WHERE membership_clubid = 1 
      AND TransMemberId IN (select LinkedMemberId from LinkedMember where MemberGroupId NOT IN (1, 2, 3, 4, 5))
      AND TransMemberId IN (select MemberLinkedId from LinkedMember where DataTransItemId = 2414)

 GROUP BY TransMemberId)

你可以检查;这个线索的结果：

WHERE TransMemberId IN (select LinkedMemberId from LinkedMember)
    AND TransMemberId IN (select LinkedMemberId from LinkedMember where MemberGroupId NOT IN (1, 2, 3, 4, 5))

与此线索相同：

WHERE TransMemberId IN (select LinkedMemberId from LinkedMember where MemberGroupId NOT IN (1, 2, 3, 4, 5))

尝试插入DISTINCT值时发生主键约束违例

1 个答案: