我有以下存储过程:
CREATE PROCEDURE myProc
@nameList varchar(500)
AS
BEGIN
create table #names (Name varchar(20))
-- split @nameList up into #names table
END
GO
@nameList
基本上会是这样的:
'John, Samantha, Bob, Tom'
答案 0 :(得分:4)
使用转换为XML
和cross apply
:
DECLARE @str varchar(50)
SET @str='John, Samantha, Bob, Tom'
SELECT names = y.i.value('(./text())[1]', 'nvarchar(1000)')
FROM
(
SELECT
n = CONVERT(XML, '<i>'
+ REPLACE(@str, ',' , '</i><i>')
+ '</i>')
) AS a
CROSS APPLY n.nodes('i') AS y(i)
输出:
names
-----
John
Samantha
Bob
Tom
编辑:它不需要proc中的临时表,所以proc将是:
CREATE PROCEDURE myProc
(@nameList varchar(500))
AS
BEGIN
SELECT names = y.i.value('(./text())[1]', 'nvarchar(1000)')
FROM
(
SELECT
n = CONVERT(XML, '<i>'
+ REPLACE(@nameList, ',' , '</i><i>')
+ '</i>')
) AS a
CROSS APPLY n.nodes('i') AS y(i)
END
但如果要将其插入临时表,则下面是示例:
create table #names
(
Name varchar(20)
)
DECLARE @str varchar(50)
SET @str='John, Samantha, Bob, Tom'
insert into #names
SELECT names = y.i.value('(./text())[1]', 'nvarchar(1000)')
FROM
(
SELECT
n = CONVERT(XML, '<i>'
+ REPLACE(@str, ',' , '</i><i>')
+ '</i>')
) AS a
CROSS APPLY n.nodes('i') AS y(i)
select * from #names
drop table #names
编辑2:输入字符串可能包含一些特殊字符,例如'<' , '>' , etc
它不是名称的标准,但如果给定的字符串包含它们,您可以使用它们删除它们replace
函数:replace(@str,'<','')
答案 1 :(得分:1)
使用递归cte:
DECLARE @nameList NVARCHAR(MAX) = 'John, Samantha, Bob, Tom'
SET @nameList = @nameList + ',';
WITH cte
AS ( SELECT SUBSTRING(@nameList, 0, CHARINDEX(',', @nameList)) AS n ,
CHARINDEX(',', @nameList) AS i
UNION ALL
SELECT SUBSTRING(@nameList, i + 2,CHARINDEX(',', @nameList, i + 2) - i - 2) ,
CHARINDEX(',', @nameList, i + 2)
FROM cte
WHERE CHARINDEX(',', @nameList, i + 2) > 0
)
SELECT n FROM cte
输出:
n
John
Samantha
Bob
Tom
答案 2 :(得分:0)
您可以创建功能并从您想要分割的地方调用此功能: -
create FUNCTION [dbo].[SplitStrings](@nameList varchar(MAX), @Delimiter char(1))
returns @temptable TABLE (names varchar(MAX))
as
begin
declare @id int
declare @x varchar(8000)
select @id = 1
if len(@nameList)<1 or @nameList is null return
while @id!= 0
begin
set @id = charindex(@Delimiter,@nameList)
if @id!=0
set @x = left(@nameList,@id - 1)
else
set @x = @nameList
if(len(@x)>0)
insert into @temptable(names) values(@x)
set @String = right(@nameList,len(@nameList) - @id)
if len(@nameList) = 0 break
end
return
end;
答案 3 :(得分:0)
CREATE FUNCTION [dbo].[Split]
(
@RowData nvarchar(MAX),
@SplitOn nvarchar(5)
)
RETURNS @RtnValue table
(
Id int identity(1,1),
Data nvarchar(100)
)
AS
BEGIN
Declare @Cnt int
Set @Cnt = 1
While (Charindex(@SplitOn,@RowData)>0)
Begin
Insert Into @RtnValue (data)
Select
Data = ltrim(rtrim(Substring(@RowData,1,Charindex(@SplitOn,@RowData)-1)))
Set @RowData = Substring(@RowData,Charindex(@SplitOn,@RowData)+1,len(@RowData))
Set @Cnt = @Cnt + 1
End
Insert Into @RtnValue (data)
Select Data = ltrim(rtrim(@RowData))
Return
END