yii 2.0 admin create无法使用ActiveForm

时间:2015-04-07 09:33:06

标签: php mysql model-view-controller yii2

好的,首先我正在使用Yii 2基本版而不是高级版。

好的,我已经做到这一点,以便我的登录功能可以从数据库中提取数据,并将其作为硬编码的用户。然后,我在索引视图中显示我的数据库中所有管理员的网格视图及其ID。我试图创建一个创建页面,管理员可以在其中创建另一个管理员。

我确实设法让这个工作,但是对于我的生活,我无法找到我做了什么使这个功能停止工作。

模型\ user.php的

<?php

namespace app\models;
use yii\base\NotSupportedException;
use yii\db\ActiveRecord;
use yii\web\IdentityInterface;
use yii\data\ActiveDataProvider;
/**
* User model
*
* @property integer $id
* @property string $username
* @property string $authkey
* @property string $password 
* @property string $accessToken
*/
class User extends ActiveRecord implements IdentityInterface
{


/**
 * @inheritdoc
 */
public static function tableName()
{
    return 'Users';
}


public function rules(){
        return [
            [['username','password'], 'required']
        ];
}



public static function findAdmins(){
    $query = self::find();

    $dataProvider = new ActiveDataProvider([
        'query' => $query,
    ]);

    return $dataProvider;

}


/**
 * @inheritdoc
 */
public static function findIdentity($id)
{
    return static::findOne(['id' => $id]);
}



/**
 * @inheritdoc
 */
public static function findIdentityByAccessToken($token, $type = null)
{
    throw new NotSupportedException('"findIdentityByAccessToken" is not implemented.');
}

/**
 * Finds user by username
 *
 * @param  string      $username
 * @return static|null
 */
public static function findByUsername($username)
{
    return static::findOne(['username' => $username]);
}

/**
 * @inheritdoc
 */
public function getId()
{
    return $this->id;
}

/**
 * @inheritdoc
 */
public function getAuthKey()
{
    return static::findOne('AuthKey');
}

/**
 * @inheritdoc
 */
public function validateAuthKey($authKey)
{
    return static::findOne(['AuthKey' => $authKey]);
}

/**
 * Validates password
 *
 * @param  string  $password password to validate
 * @return boolean if password provided is valid for current user
 */
public function validatePassword($password)
{
    return $this->password === $password;
}
}

视图\管理员\的index.php

    <?php
    use yii\helpers\Html;
    use yii\grid\GridView;

    /* @var $this yii\web\View */
    $this->title = 'Admins';
    $this->params['breadcrumbs'][] = $this->title;
    ?>
    <div class="site-about">
        <h1><?= Html::encode($this->title) ?></h1>
        <p>
            <?= Html::a('Create Admin', ['create'], ['class' => 'btn btn-success']);?>  
        </p>
        <?php
            if(isset($user_id)){
                print_r($user_id);

            }
        ?>

        <?= GridView::widget([
            'dataProvider' => $dataProvider,
            'columns' => [
                'id',
                'username',
                'password',

                ['class' => 'yii\grid\ActionColumn'],
            ],
        ]); ?> 

    </div>

这样可以正常连接我的数据库。它显示正确的列等。

现在我将向您展示两个不起作用的视图,一个呈现_form.php的create.php

视图\管理员\ create.php:

    <?php
    use yii\helpers\Html;


    /* @var $this yii\web\View */
    $this->title = 'Create Admin';
    $this->params['breadcrumbs'][] = ['label' => 'admin', 'url' => ['index']];
    $this->params['breadcrumbs'][] = $this->title;
    if(isset($username)){
    print_r($username);
    echo '</br>';
    print_r($password);   

    }
    ?>
    <div class="site-about">
        <h1><?= Html::encode($this->title) ?></h1>
        <?= $this->render('_form',[
            'model' => $model
        ]); 
        ?>



    </div>

视图\ admin_form.php:

    <?php

    use yii\helpers\Html;
    use yii\widgets\ActiveForm;



    /* @var $model app\models\Users */
    /* @var $form yii\widgets\ActiveForm */
    ?>

    <div class="admin-form">

        <?php $form = ActiveForm::begin(); ?>



        <?= $form->field($model, 'username')->textInput(); ?>
        <?= $form->field($model, 'password')->textInput(); ?>



        <div class="form-group">
            <?= Html::submitButton('create', ['class' => 'btn btn-success']) ?>
        </div>

        <?php ActiveForm::end(); ?>

    </div>

现在终于我的控制器了:

控制器\ AdminController.php:

    <?php

    namespace app\controllers;

    use Yii;
    use yii\web\Controller;
    use yii\filters\VerbFilter;
    use yii\filters\AccessControl;
    use app\models\User;





    class AdminController extends Controller
    {
        public function behaviors()
        {
            return [
                'verbs' => [
                    'class' => VerbFilter::className(),
                    'actions' => [
                        'delete' => ['post'],
                    ],
                ],
            ];
        }

        public function actions()
        {
            return [
                'error' => [
                    'class' => 'yii\web\ErrorAction',
                ],
                'captcha' => [
                    'class' => 'yii\captcha\CaptchaAction',
                    'fixedVerifyCode' => YII_ENV_TEST ? 'testme' : null,
                ],
            ];
        }

        public function actionIndex()
        {
            $searchModel = new User;
            $dataProvider = $searchModel->findAdmins();

            return $this->render('index',[
                'dataProvider' => $dataProvider
                    ]);
        }

        public function actionCreate(){
            $model = new User;

            $request = Yii::$app->request;
            $post = $request->post(); 
            $username = "usernameStandard";
            $password = "passwordStandard";
            if($model->load(Yii::$app->request->post())){
                $username = $post['User']['username'];
                $password = $post['User']['password'];
            }
            return $this->render('create',[
                'model' => $model,
                'username' => $username,
                'password' => $password
                    ]);
        }

    }

好的,所以当我尝试这样做时,我会从create.php填充表单(使用渲染的_form.php)。当我点击创建按钮。我print_r()发布结果,以确保它没有问题,它确实再次使用发布结果呈现页面。但是,它不会在我的数据库中创建新用户。

真的被困在这里有人可以帮忙吗?

1 个答案:

答案 0 :(得分:0)

嗯,您应该只是保存您的模型......例如:

public function actionCreate()
{
    $model = new User;

    if($model->load(Yii::$app->request->post()) && $model->save()) {
        return $this->redirect(['index']);
    }

    return $this->render('create',[
        'model' => $model,
    ]);
}

了解更多http://www.yiiframework.com/doc-2.0/yii-db-baseactiverecord.html#save()-detail