Question

我收到错误

语法错误在或附近＆＃34;其中＆＃34;第5行：拉链进入（选择邮政编码来自拉链的城市=＆＃39;萨克拉

当我尝试运行此代码时。

update listings
set price = CASE WHEN (listings.price IS NOT NULL) THEN (price * 
(((100+(select price_change from zips where zips.zipcode=listings.zip))/100)))
where zip in (select zipcode from zips where city = 'Sacramento');

有人看到任何容易修复的错误吗？还是我想出了一些垃圾代码？

Answer 1

SQL CASE expression需要以END关键字结束。

Answer 2

update listings
set price = CASE WHEN (listings.price IS NOT NULL) THEN (price * 
(((100+(select price_change from zips where zips.zipcode=listings.zip))/100)))
where zip in (select zipcode from zips where city = 'Sacramento')

删除;再试一次

Answer 3

在 where 子句

之前添加结束关键字

update listings
set price = CASE WHEN (listings.price IS NOT NULL) THEN (price * 
(((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) END
where zip in (select zipcode from zips where city = 'Sacramento');

根据@ a_horse_with_no_name的评论

update listings 
set price = (price * (((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) 
where zip in (select zipcode from zips where city = 'Sacramento') and listings.price IS NOT NULL

Postgresql语法错误在或附近＆＃34;其中＆＃34;

3 个答案: