我在xampp服务器上有我的数据库,我的活动和php文件如下所示。此页面中的问题是,当我运行应用程序时,它总是抛出异常。它总是显示我的最后一条消息,即“存在一些问题”。我的提交日期即将到期。
这是我的活动档案
public class AdminLoginActivity extends Activity {
TextView username, password, message;
Button SignIn;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_admin_login);
StrictMode.enableDefaults();
username = (TextView) findViewById(R.id.adminusername);
password = (TextView) findViewById(R.id.adminpassword);
message = (TextView) findViewById(R.id.textView5);
SignIn = (Button) findViewById(R.id.adminloginbtn);
SignIn.setOnClickListener(new View.OnClickListener()
{
@Override
public void onClick(View v)
{
checkAdminData();
}
});
}
public void checkAdminData()
{
InputStream isr = null;
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://localhost:1234/adminlogin.php");
try
{
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair> (2);
nameValuePairs.add(new BasicNameValuePair("username", username.getText().toString()));
nameValuePairs.add(new BasicNameValuePair("password", password.getText().toString()));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
isr = entity.getContent();
}
catch (ClientProtocolException e)
{
Log.e("log_tag", "Error in Http connection " + e.toString());
message.setText("couldn't connect to database");
}
catch (IOException e)
{
}
String responseText = null;
try
{
String res = isr.toString();
// res = res.replaceAll("\\s+", "");
if (res.equals("1")) {
Intent i = new Intent(this, AdminMainPage.class);
startActivity(i);
}
else{
message.setText("Username or Password incorrect");
}
}
catch (Exception e)
{
Log.e("log_tag", "Sorry!! Incorrect Username or Password " + e.toString());
message.setText("Some problem is there");
}
}
}
PHP文件:
<?php
$hostname_localhost ="localhost";
$database_localhost ="sibuilder";
$username_localhost ="root";
$password_localhost ="";
$localhost = mysql_connect($hostname_localhost,$username_localhost,$password_localhost)
or
trigger_error(mysql_error(),E_USER_ERROR);
mysql_select_db($database_localhost, $localhost);
$username = $_POST['username'];
$password = $_POST['password'];
$query_search = "select * from login l, admin a where a.username = '".$username."' AND l.password = '".$password. "'";
$query_exec = mysql_query($query_search) or die(mysql_error());
$rows = mysql_num_rows($query_exec);
//echo $rows;
if($rows == 0) {
echo 0;
}
else {
echo 1;
}
?>
答案 0 :(得分:0)
如果你想用你的PHP脚本代替json格式,可以参考这些问题
Android: AsyncTask to make an HTTP GET Request?
Make an HTTP request with android以处理回复。建议使用AsyncTask。