Question

我正在处理这段代码，我知道我必须调用该函数来测试它，但我不确定哪条线我称之为函数。我想打电话给sim_yahtzee（1,5）进行我的第一次测试，我怎么知道在所有这些代码行中调用它的位置？感谢

def sim_yahtzee(nrolls,n,sides=6):
    first_roll = []
    for i in range (n):
        rn = random.randint(1,6)
        first_roll.append(rn)
    number_one = first_roll.count(1)
    number_two = first_roll.count(2)
    number_three = first_roll.count(3)
    number_four = first_roll.count(4)
    number_five = first_roll.count(5)
    number_six = first_roll.count(6)
    for i in range (nrolls):
        if number_one > number_two and number_three and number_four and number_five and number_six:
            keep = [1] * number_one
        elif number_two > number_one and number_three and number_four and number_five and number_six:
            keep = [2] * number_two
        elif number_three > number_one and number_two and number_four and number_five and number_six:
            keep = [3] * number_three
        elif number_four > number_one and number_two and number_three and number_five and number_six:
            keep = [4] * number_four
        elif number_five > number_one and number_two and number_three and number_four and number_six:
            keep = [5] * number_five
        elif number_six >= number_one and number_two and number_three and number_four and number_five:
            keep = [6] * number_six
        elif number_five == number_four or number_three or number_two or number_one:
            keep = [5] * number_five
        elif number_four == number_three or number_two or number_one:
            keep = [4] * number_four
        elif number_three == number_two or number_one:
            keep = [3] * number_three
        elif number_two == number_one:
            keep = [2] * number_two
        reroll = []
        for i in range (len(first_roll)-len(keep)):
            rn = random.randint(1,6)
            reroll.append(rn)
        first_roll = (keep + reroll)
print (first_roll)

Answer 1

在python脚本中定义函数后，总是需要调用函数。在您的示例中，您可以使用

调用它

def sim_yahtzee(nrolls,n,sides=6):
    first_roll = []
    for i in range (n):
        rn = random.randint(1,6)
        first_roll.append(rn)
        number_one = first_roll.count(1)
        number_two = first_roll.count(2)
        number_three = first_roll.count(3)
        number_four = first_roll.count(4)
        number_five = first_roll.count(5)
        number_six = first_roll.count(6)
        for i in range (nrolls):
            if number_one > number_two and number_three and number_four and number_five and number_six:
                keep = [1] * number_one
            elif number_two > number_one and number_three and number_four and number_five and number_six:
                keep = [2] * number_two
            elif number_three > number_one and number_two and number_four and number_five and number_six:
                keep = [3] * number_three
            elif number_four > number_one and number_two and number_three and number_five and number_six:
                keep = [4] * number_four
            elif number_five > number_one and number_two and number_three and number_four and number_six:
                keep = [5] * number_five
            elif number_six >= number_one and number_two and number_three and number_four and number_five:
                keep = [6] * number_six
            elif number_five == number_four or number_three or number_two or number_one:
                keep = [5] * number_five
            elif number_four == number_three or number_two or number_one:
                keep = [4] * number_four
            elif number_three == number_two or number_one:
                keep = [3] * number_three
            elif number_two == number_one:
                keep = [2] * number_two
            reroll = []
            for i in range (len(first_roll)-len(keep)):
                rn = random.randint(1,6)
                reroll.append(rn)
            first_roll = (keep + reroll)
    print (first_roll)

sim_yahtzee(1,5)

另外，我已经更改了缩进，我假设循环应该在函数内部。缩进级别替换python中的end语句。

Answer 2

确保您的“for”循环正确缩进！

通过键入函数的名称并将其args作为自己的行，您可以在定义函数后调用该函数。为了从函数接收输出，您需要使用“return”语句来返回变量，因为在函数中初始化的任何变量将在函数完成后消失。

考虑放：

return first_roll

作为函数的最后一行，并使用

调用函数

print(sim_yahtzee(6,6,sides=6))

一个函数外的第一个未缩进的行。这将打印返回的变量first_roll。

我在哪里可以调用我的功能，以便测试它？

2 个答案: